3.1.2 omp_get_num_threads功能 omp_get_num_threads函数返回当前线程的数目在执行调用的并行区域的团队。 格式如下所示: #include <omp.h> int omp_get_num_threads(void); num_threads子句、omp_set_num_threads功能和OMP_NUM_THREADS环境变量控制线程数。团队。 如果线程的数目尚未由用户显式设置,默认实现中...
int omp_get_num_threads( ); 备注 有关更多信息,请参见 3.1.2 omp_get_num_threads 函数。 示例 复制 // omp_get_num_threads.cpp // compile with: /openmp #include <stdio.h> #include <omp.h> int main() { omp_set_num_threads(4); printf_s("%d\n", omp_get_num_threads( ));...
2 How to get OpenMP to work with #pragma omp task? 1 "omp parallel for" does not work in "omp parallel" 1 error: expected ‘#pragma omp’ clause before ‘{’ token 0 What's wrong with the omp declaration here? How to fix it? 1 Using omp_get_num_threads()...
一、需求缘起 Web-Server通常有个配置，最大工作线程数，后端服务一般也有个配置，工作线程池的线程数量...
int omp_get_num_threads(void); Thenum_threadsclause, theomp_set_num_threadsfunction, and theOMP_NUM_THREADSenvironment variable control the number of threads in a team. If the number of threads has not been explicitly set by the user, the default is implementation-defined. This function bind...
3.1.2 omp_get_num_threads Function Article 22/04/2008 Theomp_get_num_threadsfunction returns the number of threads currently in the team executing the parallel region from which it is called. The format is as follows: #include <omp.h> int omp_get_num_threads(void); ...
!$omp end parallel end 若是不声明OMP_GET_THREAD_NUM,OMP_GET_NUM_THREADS那么不会得到正确的线程号和总线程数。 原因:??? (2) 但是如果在开头使用"use omp_lib",则不需要声明。 但是在某些程序中还是得到 线程数 线程号为浮点数的现象 ???
!$omp end parallel end 若是不声明OMP_GET_THREAD_NUM,OMP_GET_NUM_THREADS那么不会得到正确的线程号和总线程数。 原因:??? (2) 但是如果在开头使用"use omp_lib",则不需要声明。 但是在某些程序中还是得到 线程数 线程号为浮点数的现象 ???
!$omp end parallel end 若是不声明OMP_GET_THREAD_NUM,OMP_GET_NUM_THREADS那么不会得到正确的线程号和总线程数。 原因:??? (2) 但是如果在开头使用"use omp_lib",则不需要声明。 但是在某些程序中还是得到 线程数 线程号为浮点数的现象 ???
USE omp_lib INTEGER N1, N2 N1 = omp_get_num_threads() PRINT *, N1 !$OMP PARALLEL PRIVATE(N2) N2 = omp_get_num_threads() PRINT *, N2 !$OMP END PARALLEL END Theomp_get_num_threadscall returns 1 in the serial section of the code, so N1 is assigned the value 1. N2 is assigne...