Map<String, Object> testMap =newHashMap<>(); testMap.put("name","merry"); testMap.put("age",30); testMap.put("date",newDate()); testMap.put("user",newXwjUser(1,"Hello World",newDate())); try{ String jsonStr = mapper.writeValueAsString(testMap); System.out.println("Map转...
Map<String,Object> map = JSONObject.parseObject(JSON.toJSONString(findArchiveDto)); //Map转Object FindArchiveDto findArchiveDto1 = JSON.parseObject(JSON.toJSONString(map), FindArchiveDto.class); FindArchiveDto findArchiveDto2 = JSONObject.toJavaObject(JSON.toJSONString(map), FindArchiveDto.clas...
Map<String, Object> testMap = new HashMap<>(); testMap.put("name", "22"); testMap.put("age", 20); testMap.put("date", new Date()); testMap.put("student", new Student("hyl", 20, new Date())); String jsonStr = mapper.writeValueAsString(testMap); System.out.println(json...
Map<String, Object> testMap = new HashMap<>(); testMap.put("name", "22"); testMap.put("age", 20); testMap.put("date", new Date()); testMap.put("student", new Student("hyl", 20, new Date())); String jsonStr = mapper.writeValueAsString(testMap); System.out.println(json...
//2.把Json转换成map,必须使用 TypeReference , map的类型定义 可以根据实际情况来定,比如若值都是String那么就可以 Map Map System.out.println(map: + userBaseMap.get(userName));//3.list List System.out.println(list: + userBaseList.get(0).getUserName());//4.Bean[] 数组,必须...
letJSONString=NSString(data:dataasData,encoding:String.Encoding.utf8.rawValue)// 需要传[String: Any]格式数据,也就是字典即可letmodel1=Mapper<TestWSModel>().map(JSON: dic) // 传Any也就是任何格式数据都可以,但是我们点进去后可以发现,如果不是[String: Any]格式,直接返回nil let model2 = Mapper...
false);// 将对象转换成 JSON 字符串MyObjectobj=newMyObject();Stringjson=mapper.writeValueAsString...
打印处理的是 null,22,说明key变成了String。怎么解决这个问题,看下代码:很简单只要转化的时候讲Object.class转化成map.getClass();,就可以了,结果输出的是 22,null jackson ObjectMapper 序列化成json 属性值为null时转换为""空字符串 import java.io.IOException;import org.codehaus.jackson.JsonGeneration...
rxProvider.request(.login(username:"username",password:"password")).mapJSON().subscribe(onNext:{jsonindebugPrint(json)//已经帮你转成了 JSON,在这里只需要拿到JSON进行接下来的逻辑就可以了}).addDisposableTo(disposeBag) 还可以mapString .mapString(atKeyPath: "") ...
return map; } public static void main(String[] args) throws Exception { Options opts = new OptionsBuilder() .include(ObjectMapperTest.class.getSimpleName()) .resultFormat(ResultFormatType.CSV) .build(); new Runner(opts).run(); }