phi=(1+np.sqrt(5))/2print("Phi",phi)#2\.Find the index below4million n=np.log(4*10**6*np.sqrt(5)+0.5)/np.log(phi)print(n)#3\.Create an arrayof1-n n=np.arange(1,n)print(n)#4\.Compute Fibonacci numbers fib=(phi**n-(-1/phi)**n)/np.sqrt(5)print("First 9 Fibona...
2)==1condarray([False, True, False, True, False, False, False, True, False, True, False, True])# Use extract to get the valuesnp.extract(cond, array)array([ 1, 19, 11,
Get close prices. today = date.today() start = (today.year - 1, today.month, today.day) quotes = quotes_historical_yahoo(sys.argv[1], start, today) close = numpy.array([q[4] for q in quotes]) print pos_confidence(close) AAPL程序的输出如下: 代码语言:javascript 代码运行次数:0 运行...
Finding the nearest value and return the index of array in Python我找到了这篇文章:python:在数组中查找元素 它是通过匹配值返回数组的索引。 另一方面,我想做的是相似但不同的事情。我想找到目标值的最近值。例如,我在寻找4.2,但我知道数组中没有4.2,但我想返回值4.1的索引,而不是4.4。 最快的方法是什么...
assert_array_almost_equal函数 有时我们需要检查两个数组是否几乎相等。 如果两个数组的指定精度不相等,assert_array_almost_equal函数将引发异常。 该函数检查两个数组的形状是否相同。 然后,将数组的值按元素进行如下比较: |expected - actual| <0.510-decimal ...
(506,)## We will consider "lower status of population" as independent variable for its importancelstat = x[0:,-1]lstat.shape(506,)from scipy import statsslope, intercept, r_value, p_value, std_err = stats.linregress(lstat, y)print(slope, intercept, r_value, p_value, std_err)-...
In this case, it ensures the creation of an array object compatible with that passed in via this argument. .. versionadded:: 1.20.0np.arange() 与 np.array(range()) 类似,但前者允许用浮点数>>> np.arange(12) array([ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]) >>> np....
In [8]: x2 = np.sin(2* np.pi *20* time) In [9]: x3 = np.sin(2* np.pi *60* time) In [10]: x += x2 + x3 In [11]: y = np.fft.fft(x) In [12]: show(x, y) 首先,我们再创建两个频率不同的正弦波,频率为 20Hz 的x2和 60Hz 的x3,然后将它们添加到原始的 1Hz 正...
Element index to partition by. The k-th value of the element will be in its ...
cond = np.mod(array, 2)==1 cond array([False, True, False, True, False, False, False, True, False, True, False, True])# Use extract to get the values np.extract(cond, array)array([ 1, 19, 11, 13, 3])# Applycondition on extract directly np.extract(((array < 3) |...