Which of the following numbers is divisible by 3 but not divisible by 9?A.333B.2015C.2016D.12345 答案 D哪个数可以整除3不能整除9?考察3和9的整除特征: 各位数字之和能被3整除,则这个数能被3整除;各位数字之和能被9整除,则这个数能被9整除.相关推荐 1Which of the following numbers is divisible...
The best approach to solving this problem is to find one number that is divisible by both 3 and 8, and then determine which of the answer choices also goes into that number. When you multiply 3 times 8, you get 24, which means that 24 is one number that is divisible by both 3 and...
Find an integer between 100 and 150 divisible by 9. What is the number of integers from (999, 9999) that are divisible by 4 and are not divisible by 5? Determine the sum of the integers among the first 1000 positive integers which are not divisible by 4 or are not divisible...
Check whether the given numbers are divisible by '8' or not : 76728 01:44 Check whether the given numbers are divisible by 7 or not : 427 02:08 Check whether the given numbers are divisible by 7 or not : 3514 05:02 Check whether the given numbers are divisible by 7 or not : 861...
For any digit number to be divisible by 3, the sum of the digits of the number should be a multiple of 3 or divisible by 3. In the case of 2 digit...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can answer ...
And finally, we add the number of elements in each set. 1+4+7+9+6+3=30. A number divisible by 3 has all its digits add to a multiple of 3. The last two digits are 2 and 3 and add up to 5≡2(mod3). Therefore the first two digits must add up to 1(mod3)⋅4 digits ...
A number divisible by 8(such as 8)may not be divisible by 6, but is divisible by 1,2, and 4. 下列哪个数字不能被8整除( ). A.6 B.4 C.2 D.1 可以被8整除的数字(例如8)可能不能被6整除,但是可以被1,2和4整除, 故选A.反馈
Write a Java program to print numbers between 1 and 100 divisible by 3, 5 and both. Pictorial Presentation: Sample Solution: Java Code: publicclassExercise50{publicstaticvoidmain(Stringargs[]){// Print numbers divided by 3System.out.println("\nDivided by 3: ");for(inti=1;i<100;i++)...
To solve the problem of finding how many numbers divisible by 5 and lying between 4000 and 5000 can be formed from the digits 4, 5, 6, 7, and 8 (with repetition of digits allowed), we can follow these steps:1. Identify the Range
Representation of numbers, divisible by a large square, by a positive ternary quadratic formOne gives a generalization of the Linnik-Malyshev theorem (A. V. Malyshev, Tr. Mosk. Inst. Akad. Nauk, Vol. 65, 1962, Chap. V, Sec. 2) to arbitrary integral positive ternary quadratic forms....