百度试题 结果1 题目2. Circle the numbers below that are divisible by both 3 and 4.15-24-30-48 相关知识点: 试题来源: 解析 ‘24'and '48' circled 反馈 收藏
And finally, we add the number of elements in each set. 1+4+7+9+6+3=30. A number divisible by 3 has all its digits add to a multiple of 3. The last two digits are 2 and 3 and add up to 5≡2(mod3). Therefore the first two digits must add up to 1(mod3)⋅4 digits ...
To solve the problem of finding the number of numbers divisible by 3 that can be formed using four different even digits, we can follow these steps:Step 1: Identify the even digits The even digits available are 0, 2, 4, 6, and
4) Number divisible by 5 Units digit is either zero or five Ex:50, 20, 55, 65, etc 5) Number divisible by 6 The number is divisible by both 2 and 3 EX: 168 Last digit = 8 --- (8 is divisible by 2) Sum of digits = (1 + 6 + 8) = 15 --- (divisible by 3) Hence...
B.The last two digits are divisible by 4. C.The last three digits are divisible by 4. D.The sum of the digits within it is divisible by 4.相关知识点: 试题来源: 解析 B Multiples of 4 are characterized by their last two digit divisible by 4.反馈...
The best approach to solving this problem is to find one number that is divisible by both 3 and 8, and then determine which of the answer choices also goes into that number. When you multiply 3 times 8, you get 24, which means that 24 is one number that is divisible by both 3 and...
Using divisibility tests, determine which of the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11 (say, yes or no): 1/2⋅(-1)^2÷1/2⋅(-1)^2=1/2⋅(-1)^2=1/2.
A number divisible by 8(such as 8)may not be divisible by 6, but is divisible by 1,2, and 4. 下列哪个数字不能被8整除( ). A.6 B.4 C.2 D.1 可以被8整除的数字(例如8)可能不能被6整除,但是可以被1,2和4整除, 故选A.反馈
3 of the 4 numbers listed in the choices given for this problem will not be divisible by( ).A. 6 B. 10 C. 14 D. 15 相关知识点: 试题来源: 解析 C Any multiple of 2×3×5=30 will be divisible by 6,10 and 15, but not by 14. 下面选项中除了哪个选项,其他3个选项都能够被整除...
Which ones are divisible by 4? 234 789 7756 8865 3728 8064相关知识点: 试题来源: 解析 能被2整除:234,7756,3728,8064. 能被5整除:8865; 能被4整除:7756,3728,8064. 被2整除:末尾是2,4,6,8,0; 被4整除:末两位是4的倍数即可; 被5整除:末尾是0或5.反馈...