Given a strings,returnthe maximum number of unique substrings that the given string can be split into. You can split stringsinto any list of non-empty substrings, where the concatenation of the substrings forms the original string. However, you must split the substrings such that all of the...
代码参考: 1classSolution {2public:3voidbacktrack(int& res,intpos,string& s, unordered_set<string>&path) {4if(pos==s.length()) {5res = max(res, (int)path.size());6return;7}8for(inti=pos+1; i<=s.length(); i++) {9stringcur = s.substr(pos, i-pos);10if(path.count(cur...
Given a strings,returnthe maximum number of unique substrings that the given string can be split into. You can split stringsinto any list of non-empty substrings, where the concatenation of the substrings forms the original string. However, you must split the substrings such that all of the...
1715. Split a String Into the Max Number of Unique Substrings Medium Given a string s, return the maximum number of unique substrings that the given string can be split into. You can split string s into any list of non-empty substrings, where the concatenation of the sub...
Tight bounds on the maximum number of shortest unique substringsdoi:10.4230/LIPICS.CPM.2017.24Takuya MienoShunsuke InenagaHideo BannaiMasayuki TakedaSchloss Dagstuhl- Leibniz-Zentrum fur Informatik GmbH, Dagstuhl PublishingCombinatorial Pattern Matching
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2. Substring in a string with overlap Consider a string where there could be a overlap of given sub-string. For exampleaaahas overlap of sub-stringaaand if you consider the overlap while counting, the number of occurrences would be twice. ...
Step 2 - Compare substrings to a lookup table The equal sign lets you compare value to value, you can also compare array to array as long as the first array is horizontal and the second array is vertical or vice versa. TEXTSPLIT(B3, ";")=$E$3:$E$11 ...
链接:https://leetcode-cn.com/problems/split-a-string-into-the-max-number-of-unique-substrings/ 难度:medium 题目描述:给定一个字符串,要求切分出尽可能多的各不相同的子串。其实最多也就是一个字母一个子串,结果为s.length()。这里用了暴力解加上回溯以及相应的剪枝。
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