C++ code to find trailing zeros in factorial of a number#include<bits/stdc++.h> using namespace std; int trailingZeros(int n){ int count=0; if(n<0) return -1; for(int i=5;n/i>0;i*=5){ count+=n/i; } return count;
public int trailingZeroes(int n) { int result = 0; while(n > 0){ n = n/5; result += n; } return result; } } 需要注意 个别数 5^n;
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