C++ code to find trailing zeros in factorial of a number#include<bits/stdc++.h> using namespace std; int trailingZeros(int n){ int count=0; if(n<0) return -1; for(int i=5;n/i>0;i*=5){ count+=n/i; } return count;
codewars--js--Number of trailing zeros of N!问题描述:Write a program that will calculate the number of trailing zeros in a factorial of a given number.N! = 1 * 2 * 3 * ... * NBe careful 1000! has 2568 digits...For more info, see: http://mathworld.wolfram.com/Factorial.htmlE...
"; cin >> number;if(number > 0){while(storeCount <= number) { storeMultiplication = storeCount * 1; factorial *= storeCount; storeCount++; } cout <<"the factorial of "<< number <<"!"<<" is "<< factorial; }else{ cout <<"Please introduce a positive integer. "; }return0; }...
public class Solution { public int trailingZeroes(int n) { int result = 0; while(n > 0){ n = n/5; result += n; } return result; } } 需要注意 个别数 5^n;
Private Function Factorial(ByVal subnumber As Integer) As Long Dim temp As Long temp = 1 Dim i As Integer For i = 1 To subnumber temp = temp * i Next i Factorial = temp End Function Private Sub Form_Load() Me.AutoRedraw = True Me.FontSize = 20 Dim i As Integer Dim sum As ...
1publicclassSolution {2/**3*@paramnums: A list of integers4*@paramk: As described5*@return: The majority number6*/7publicintmajorityNumber(ArrayList<Integer> nums,intk) {8if(nums ==null|| nums.size() == 0) {9returnInteger.MIN_VALUE;10}1112//most k - 1 values in the map13Hash...