Given an array of integersnumsand an integertarget. Return the number of non-empty subsequences ofnumssuch that the sum of the minimum and maximum element on it is less or equal totarget. Since the answer may be too large, return it modulo109 + 7. Example 1: Input: nums = [3,5,6,...
Zero-sum subsequencesSuppose $G$ is a finite abelian group and $S=g_{1}\\\cdots g_{l}$ is a sequence of elements in $G$. For any element $g$ of $G$ and $A\\\subseteq\\\mathbb{Z}\\\backslash\\\left\\\{ 0ight\\\} $, let $N_{A,g}(S)$ denote the number of ...
count-number-of-homogenous-substrings.c count-number-of-nice-subarrays.c count-number-of-special-subsequences.c count-number-of-teams.c count-numbers-with-unique-digits.c count-odd-numbers-in-an-interval-range.c count-of-matches-in-tournament.c count-of-range-sum.c count-of-...
1621-number-of-subsequences-that-satisfy-the-given-sum-condition 1627-last-moment-before-all-ants-fall-out-of-a-plank 1637-string-compression-ii 1642-water-bottles 165-compare-version-numbers 1653-number-of-good-leaf-nodes-pairs 1657-find-the-winner-of-an-array-game 1666-make-the-stri...
Explanation: The length of longest continuous increasing subsequence is 1, and there are 5 subsequences' length is 1, so output 5. Note: Length of the given array will be not exceed 2000 and the answer is guaranteed to be fit in 32-bit signed int. ...
For every i < j with A[i] < A[j], we might append A[j] to a longest subsequence ending at A[i]. It means that we have demonstrated count[i] subsequences of length length[i] + 1. Now, if those sequences are longer than length[j], then we know we have count[i] sequences...
Learn how to determine the maximum number of strings that can have a common prefix of a specified length K.
For any sequence S, let the width of S be the difference between the maximum and minimum element of S. Return the sum of the 115. Distinct Subsequences(不同的子序列) 题目链接:https://leetcode.com/problems/distinct-subsequences/ Given a string S and a string T, count the number of ...
#include <bits/stdc++.h> using namespace std; class Solution { public: int numSubmatrixSumTarget(vector<vector<int>>& matrix, int target) { int ans = 0; int col = matrix[0].size(); int row = matrix.size(); for(int i = 0; i < row; i++){ for(int j = 1; j < col; ...
version of a result of Bollobás and Leader. As a corollary, one obtains a result of Adhikari, Chen, Friedlander, Konyagin and Pappalardi. A result of Yuan and Zeng on the existence of zero-smooth subsequences and the DeVos–Goddyn–Mohar Theorem are some of the main ingredients of our ...