RecentCounter() { }intping(intt) { Qping.push(t);while(!Qping.empty()) {if((t-Qping.front()) >3000) { Qping.pop(); }else{break; } }returnQping.size(); }protected: queue<int>Qping; };
Can you solve this real interview question? Number of Recent Calls - You have a RecentCounter class which counts the number of recent requests within a certain time frame. Implement the RecentCounter class: * RecentCounter() Initializes the counter wi
题目的意思是每次调用RecentCounter类的ping方法时,计算[t-3000,t]范围内的数有多少,而t每次都会增加,也就是说,由多次调用ping方法组成的t数组,是一个递增数组,而我们只需要每次拿到新的t时,计算[t-3000,t]内的t有多少个。 使用List存储每次调用ping方法时传入的t,然后计数[t-3000,t]内的元素个数。 class...
4.1 RencentCounter 类 classRecentCounter:## 定义一个类 RecentCounterdef__init__(self):self.q=collections.deque()## 实例化defping(self,t:int)->int:## 定义 ping 方法,参数是时间 t;返回的是有效请求次数self.q.append(t)whileself.q[0]<t-3000:self.q.popleft()returnlen(self.q) 4.2 在Ju...
Write a class RecentCounter to count recent requests. It has only one method: ping(int t), where t represents some time in milliseconds. Return the number of pings that have been made from 3000 milliseconds ago until now. Any ping with time in [t - 3000, t] will count, including the...
109th LeetCode Weekly Contest Number of Recent Calls Write a classRecentCounterto count recent requests. It has only one method:ping(int t), where t represents some time in milliseconds. Return the number ofpings that have been made from 3000 milliseconds ago until now....
* @lc app=leetcode id=933 lang=golang * * [933] Number of Recent Calls */ // 148 ms 59.82 % type RecentCounter struct { buf []int // 缓存t }func Constructor() RecentCounter { return RecentCounter{ buf: []int{}, } }func (this *RecentCounter) Ping(t int) int { ...
Number of 1 Bits 初步想法就是沿用上题190的思路,右移n,然后不断按位与操作来进行计数。 当然也可以用我以前面试的时候答的转成字符串哈哈哈~ 参考链接 191. Number of 1 Bits | 汉明重量几种解法...Leetcode 200. Number of Islands 问题描述:找出孤岛的个数,孤岛定义为多个连接的1,被4个0包围,上下...
Submit your solution:https://leetcode.com/problems/find-the-duplicate-number/ Sorting O(nlogn) If we sort the numbers (the complexity is O(nlogn)), we can just check (O(n)) from the start to the end for any two neighbouring numbers. ...
写一个RecentCounter类来计算最近的请求。 它只有一个方法:ping(int t),其中t代表以毫秒为单位的某个时间。 返回从 3000 毫秒前到现在的ping数。 任何处于[t - 3000, t]时间范围之内的ping都将会被计算在内,包括当前(指t时刻)的ping。 保证每次对ping的调用都使用比之前更大的t值。