3. After iterating all cells in input matrix in step 2, we've got all the contribution count of 1s in M with positions mapped to the top-left sub-matrix. Since we want to maximize the total number of 1s in M, we sort this count in descending order and add the first maxOnes count...
ones,one = 0,0 add = 0 m = 1 if n <= 0: return 0# different part with the code above a = n# different part with the code above while a:# different part with the code above a = n/m#数字的左边部分 b = n%m#数字的右边部分 one = (a + 8) / 10 * m ones += one add...
题目地址:https://leetcode-cn.com/problems/number-of-distinct-islands/题目描述Given a non-empty 2D array grid of 0’s and 1’s, an island is a group of 1’s (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded...
int a = n / m, b = n % m; ones += (a + 8) / 10 * m + (a % 10 == 1) * (b + 1); } return ones; } 代码很短,重点就在这行: ones += (a + 8) / 10 * m + (a % 10 == 1) * (b + 1); 什么意思呢,实际上高票的思路非常聪明,他不是按数字顺序来直接计数的,...
【leetcode】在一堆每个数字都出现三次的数组中,找到那个只出现一次的数(Single Number II),题目的描述是这样的:Givenanarrayofintegers,everyelementappears three timesexceptforone.Findthatsingleone.Note:Youralgorithmshouldhavealinearruntimecomplexity.Couldyou
publicintcountDigitOne(intn){intcount=0;for(longk=1;k<=n;k*=10){longr=n/k,m=n%k;// sum up the count of ones on every place kcount+=(r+8)/10*k+(r%10==1?m+1:0);}returncount;} 总 这道题的话,就是数学的分类、找规律的题目了,和172 题找阶乘中0的个数一样,没有一些通...
Explanation:The input binary string00000000000000000000000010000000has a total of one '1' bit. Example 3: Input:11111111111111111111111111111101 Output:31 Explanation:The input binary string11111111111111111111111111111101has a total of thirty one '1' bits. ...
最后求结果的时候,遍历 map,把里面距离大于 2 的 key 都拿出来,value 对应的是个数,在这些个数里面任取 2 个点就是解,所以利用排列组合,C n 2 就可以得到这个距离的结果,最后把这些排列组合的结果累积起来即可。 代码# Go packageleetcodefuncnumberOfBoomerangs(points[][]int)int{res:=0fori:=0;i<le...
Leetcode 137 Single Number II Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
LeetCode 5247. Minimum Swaps to Make Strings Equal Minimum Swaps to Make Strings Equal Difficulty: Easy You are given two strings s1 and s2 of equal length consisting of letters “x” and “y” only. Your task is to make these two ......