【摘要】 problem D. Number into Sequence time limit per test3 seconds memory limit per test256 megabytes input... problem D. Number intoSequence time limit per test3 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given an integer n (n>1). Your ...
kk is themaximum possible (i. e. the length of this sequence is themaximum possible). If there are several such sequences, any of them is acceptable. It can be proven that at least one valid sequence always exists for any integern>1n>1. You have to answertt independent test cases. I...
If there are several such sequences, any of them is acceptable. It can be proven that at least one valid sequence always exists for any integern>1n > 1n>1. You have to answertttindependent test cases. The first line of the input contains one integerttt(1≤t≤50001 \le t \le 50001...
后面懒得写了,我也是参考了大佬的博客,他写得很详细了,主要讲讲初始化f数组的时候,题目定义的斐波那契数列f[0] = 1,所以f数组的前2∗k+1项都是1. 大佬的博客--->Go Code #include<iostream> #include<cstring> using namespacestd; typedeflonglongLL; constintN =85,M=1000000007; inta[N][...
CodeForces 392C Yet Another Number Sequence 矩阵快速幂,题意:$F_n$为斐波那契数列,$F_1=1,F_2=2$。给定一个$k$,定义数列$A_i=F_i\cdoti^k$。求$A_1+A_2+\cdots+A_n$。分析:构造一个列向量,${\begin{bmatrix}F_{i1}i^0&F_{i1}i^1&\c
xhSong posted @ 2014年2月20日 00:31 in 数学 with tags 数学 codeforces 392c 矩阵快速幂 Yet Another Number Sequence , 2309 阅读 题目大意 已知斐波那契数列F1 = 1, F2 = 2, Fi = Fi - 1 + Fi - 2 (i > 2)。定义Ai(k) = Fi × ik (i...
In the first sample the sequence of numbers that Petya gets as he tries to obtain numberbis as follows: 10 → 8 → 6 → 4 → 3 → 2 → 1. In the second sample one of the possible sequences is as follows: 6 → 4 → 3....
Everyone knows what the Fibonacci sequence is. This sequence can be defined by the recurrence relation: F1 = 1, F2 = 2, Fi = Fi - 1 + Fi - 2(i > 2). We'll define a new number sequenceAi(k) by the formula: ...
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To solve it we should look on how sequence behaves modulo . We may see that it actually can be split into several arithmetic progressions with step : we increase current number until it's not less than , that is . At this point we subtract from this number and obtain number . Since th...