NTT's NGN migration plan gains urgency
LTE successor systems (e.g., referred to as Future Radio Access (FRA), 5th generation mobile communication system (5G), 5G+ (plus), New Radio (NR), New radio access (NX), Future generation radio access (FX), LTE Rel. 15 or later) are also under study. ...
称它们在位置 \(p\) 匹配,当且仅当对于任意 \(i\in[0,m)\),有 \(s_{p-m+i+1}=t_i\)。不难发现它的充分条件为 \(\sum_{i=0}^{m-1}(s_{p-m+i+1}-t_i)^2=0\)。展开,得到 \(\sum_{i=0}^{m-1}(s^2_{p-m+i+1}+t^2_{i}-2s_{p-m+i+1}t_i)=0\)。注意到前...
The first to jointly launch a Fido ecosystem with multiple mobile device manufacturers — with devices including the Fujitsu NX Arrows F-04G, Sharp Aquos SH-03 and Samsung’s Galaxy S6 and Galaxy S6 Edge, all coming preloaded with NTT Docomo ID and Fido-support; The first to offer a mobi...
TOKYO, March 23, 2016 /PRNewswire/ -- NTT Resonant's Oshiete! goo Launches 'goo Shuo!' Q&A Service for Chinese Visitors
设$S_n=\sum_{i=0}^nx^i$,则$xS_n=\sum_{i=1}^{n+1}x^i$,得$S_n=\frac{x^{n+1}-1}{x-1}$,即$g(x)=\frac{x^{n+1}-1}{(x-1)x!}\tag !$。特殊的,令$g(0)=1,g(1)=n+1$。这样$f,g$都可以递推。然后 $$Ans=\sum_{j=0}^n2^j\cdot j!\cdot(f*g)(j)$...
"洛谷" "Codeforces" 思路 看到计数和$998244353$,可以感觉到这是一个DP+生成函数+NTT的题。 设$s_i$表示$i$是否在集合中,$A$为$s$的生成函数,即$A(x)=\sum_n s_nx^n$。 设$f_n$为有$n$分时二
In the autumn of 2005, the world's UMTS operators took a key step towards delivering on the promise of true mobile internet service. Six years of disappoin... A Harrowell - 《Mobile Communications International》 被引量: 0发表: 2006年 ...
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