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今天在看一道我一直比较怕的题,“数组中的第K个最大元素”,结果发现用 std::nth_element 就可以了,具体原理看了一下源码。 gcc/libstdc++-v3/include/bits/stl_algo.h at d9375e490072d1aae73a93949aa158fcd2a27018 · gcc-mirror/gcc (github.com)github.com/gcc-mirror/gcc/blob/d9375e490072d1...
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Slides: https://github.com/boostcon CppNow Website: https://www.cppnow.org CppNow Twitter: @CppNow --- The Nth Element: A Case Study - Kris Jusiak - CppNow 2022 Variadic packs have been with us since C++11, however getting the nth element efficiently out of a variadic pack still ...
作用:nth_element作用为求第n大的元素,并把它放在第n位置上,下标是从0開始计数的,也就是说求第0小的元素就是最小的数。 如:a[start,end]元素区间。排序后a[n]就是数列中第n+1大的数(下标从0開始计数)。要注意的是a[start,n), a[n,end]内的大小顺序还不一定。
STL中的nth_element()方法的使用 通过调用nth_element(start, start+n, end) 方法可以使第n大元素处于第n位置(从0开始,其位置是下标为 n的元素),并且比这个元素小的元素都排在这个元素之前,比这个元素大的元素都排在这个元素之后,但不能保证他们是有序的,下面是这个方法的具体使用方法. ...
它的用法是nth_element(a+l,a+k,a+r) 这样它会使a这个数组中区间[l,r)[l,r)内的第kk小的元素处在第kk个位置上(相对位置) 但是它并不保证其他元素有序! 不过根据网友的实验,貌似在vs上是有序的,不过在dev中是无序的 时间复杂度:O(n)O(n) ...
The code for this article is available on GitHub The function we passed to the Array.filter() method gets called with each element in the array. On each iteration, we use the modulo % operator to check if the remainder of dividing the current index by n is 0. The modulo operator return...
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