Can you solve this real interview question? Nth Magical Number - A positive integer is magical if it is divisible by either a or b. Given the three integers n, a, and b, return the nth magical number. Since the answer may be very large, return it modulo
n is positive and will fit within the range of a 32-bit signed integer (n < 231). Example 1: Input: 3 Output: 3 Example 2: Input: 11 Output: 0 Explanation: The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, … is a 0, which is part of the numb...
https://github.com/grandyang/leetcode/issues/878 参考资料: https://leetcode.com/problems/nth-magical-number/ https://leetcode.com/problems/nth-magical-number/discuss/154613/C%2B%2BJavaPython-Binary-Search https://leetcode.com/problems/nth-magical-number/discuss/154965/o(1)-Mathematical-Solution...
这样题目就从找出第N个Magical Number变成判断一个数是否是第N个Magical Number。假设n是其中一个Magical Number,显然n满足 n % A == 0 或者 n % B == 0。对于A来说,从A到n之间有n/A个Magical Number,而对B来说是n/B个Magical Number。但是n却并不是第(n/A + n/B)个Magical Number,因为这两者之...
2、:nth-of-type(n) :nth-of-type(n) 选择器匹配属于父元素的特定类型的第 N 个子元素的每个元素,n 可以是数字、关键词或公式。 3、具体区别 首先看代码 p:nth-of-type(7) 选择的 p元素所在的父元...猜你喜欢算法作业第四周(leetcode)——878. Nth Magical Number 感觉随机抽的题目从第二周以来...
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while lo < hi: mid = lo + (hi - lo) // 2 if check(mid): lo = mid + 1 else: hi = mid return lo % mod # N, A, B = 4, 2, 3 N, A, B = 5, 2, 4 print(Solution().nthMagicalNumber(N, A, B))