https://leetcode.com/problems/remove-nth-node-from-end-of-list/ 题目: nth For example, AI检测代码解析 Given linkedlist:1->2->3->4->5,andn=2.After removing the second node from the end,the linkedlistbecomes1->2->3->5. 1. 2. 3. Note: Given n will always be valid. Try to d...
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given n will always be valid. Try to d...
【LeetCode】26.Linked List —Remove Nth Node From End of List 从列表末尾删除第n个节点 Given a linked list, remove then-th node from the end of list and return its head. Example: Given linked list:1->2->3->4->5, andn= 2. After removing the second node from the end, the linked...
Given a linked list, remove then-th node from the end of list and return its head. Example: Given linked list: 1->2->3->4->5, andn= 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Givennwill always be valid. Follow up: Could yo...
19. Remove Nth Node From End of List Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. ...
Remove Nth Node From End of List 2. Solution Version 1 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution{public:ListNode*removeNthFromEnd(ListNode*head,intn){if(!head||...
Can you solve this real interview question? Remove Nth Node From End of List - Given the head of a linked list, remove the nth node from the end of the list and return its head. Example 1: [https://assets.leetcode.com/uploads/2020/10/03/remove_ex1.j
Given the head of a linked list, remove the nth node from the end of the list and return its head.impl Solution { pub fn remove_nth_from_end(head: Option<Box<ListNode>>, n: i32) -> Option<Box<ListNode>> { let mut dummy = Some(B
简介: LeetCode 19. 删除链表的倒数第N个节点 Remove Nth Node From End of List LeetCode 19. 删除链表的倒数第N个节点 Remove Nth Node From End of ListTable of Contents一、中文版二、英文版三、My answer四、解题报告一、中文版给定一个链表,删除链表的倒数第 n 个节点,并且返回链表的头结点。
原问题链接:https://leetcode.com/problems/remove-nth-node-from-end-of-list/ 问题分析 这个问题相对来说比较简单。因为要删除链表中从后往前的第n个元素,所以需要用一个元素first的引用先往前n步,然后再用一个引用second跟着这个元素一步步到链表的最后。既然要删除这个倒数第n的元素,可以在第二个元素后面跟一...