Closed Whenever i try to to convert my string file to any other language, it gives me following exception. This is not a JSON Array.: This is not a JSON Array. java.lang.IllegalStateException: This is not a JSON Array. at com.google.gson.JsonElement.getAsJsonArray(JsonElement.java:106...
JSONObject user = findByPCAndUserVo(userId, config.getHttpsUrlUserAuth(), 1, request); String deptName = ""; String companyName = ""; if (user.containsKey("departmentVos")) {//一定要记住判断此对象是否存在 JSONArray data = user.getJSONArray("departmentVos"); for (int i = 0; i <...
com.businessobjects.report.web.json.JSONException: JSONObject["ancestors"] is not a JSONArray. at com.businessobjects.report.web.json.JSONObject.getJSONArray(JSONObject.java:456) at com.businessobjects.report.web.shared.JSONParameter.getDiscreteValueFromJSON(JSONParameter.java:708) at com.businessob...
解决办法: JSONArray okJsonArray = new JSONArray(jsonParam.get("").toString()); 或 JSONArray okJsonArray = (JSONArray) jsonParam.get(“id_name”);
import net.sf.json.*; public class ResolveJson { public static void main(String[] args) { String json = "{\"data\":{\"items\":[{\"itemstring\":\"手机\",\"itemcoord\":{\"x\":0,\"y\":100,\"width\":40,\"height\":20},}],\"session_id\":\"\",},\"code\":0,\"me...
I wrapped data = printData.getJSONObject(i); around a try/catch block. If it hits a ESCPOS command it'll continue with the loop, thereby winding up the array. In this way, I am able to get the { type:'raw', format:'image', flavor:'file', data: image_url, options:{language:...
错误:JSONObject[“data”] is not a JSONArray JSONObject[“data”] 不是一个 JSONArray 原因: JSONObject json = AcceptUtil.acceptFile(req); JSONArray data = json.getJSONArray(“data”); 先从前端获取JSONObject 里的数据,再获取JSONObject 里的data数组,这里会存在一个问题,data如果没有值就会报上...
InvalidJSON Array parsing error,{ParameterName} Specified parameter JSON Array parsing error, {ParameterName} is not valid. 参数值JSON解析错误,不是正确的JSON格式。 400 MalformedPOSTRequest Invalid json string. 请求的格式错误。 403 AccessDenied %s 访问权限错误,没有访问权限。 400 Throttling.Api The ...
既然我们已经了解了TypeError: a.slice is not a function这个问题的原因,下面我们就来介绍一些解决方案。 1. 检查数据类型 首先,我们应该确保在使用slice方法之前,变量a的数据类型符合我们的预期。 在期望a是数组的情况下,可以使用Array.isArray()来检查a是否为数组类型。如果不是数组,可以通过其他方式将其转换为数...
}elseif(Array.isArray(data)) {letresult=data.map((it)=>{// 1#: If any such values are encountered during conversion they are either omitted (when found in an object) or changed to null (when found in an array).returncommonKeys1.includes(typeofit)?'null':jsonstringify(it) ...