方法一:利用一个字典和一个列表解决,字典记录每个字符出现的次数,列表记录出现过的字符,从前到后遍历这个string 遇到新字符(字典中没有的key),在字典中添加key为该字符,value为1,列表中append该字符 遇到出现过的字符(字典中有该key),字典中该key的value加1 然后,遍历列表,打印出value为1的字符即可 代码如下 1 ...
The first non-repeating character so far is: g Reading: d The first non-repeating character so far is: g Reading: i The first non-repeating character so far is: g Reading: s The first non-repeating character so far is: g Reading: g The first non-repeating character so far is: o R...
You are given a string str consisting of lowercase Latin letters. Find the first non-repeating character in str. Note: You have to traverse the string only once. See original problem statement here Tets Case: Input: prepbytes Output: 1 Explanation: In the string 'prepbytes', we start trave...
Program to find first non-repeating character in a string in Kotlinpackage com.includehelp.basic import java.util.* fun getFirstNonRepeatedChar(str: String): Char? { val characterHashMap: HashMap<Char, Int> = HashMap<Char, Int>() var c: Char // Scan string and build hash table for(...
First non-repeating character in a stream Given an input stream of n characters consisting only of small case alphabets the task is to find the first non repeating character each time a character is inserted to the stream. Example Flow in stream : a, a, b, c ...
The method may include identifying locations in a mask value to store the unique random value and locations in a mask value to store filler values. The mask value may include different character sets and may comply with user specified formats. The method may include generating a set of ...
[Algorithm] 387. First Unique Character in a String 2019-12-13 22:36 −Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0... ...
If a string contains all repeating characters, it should return an empty string ("") or None. 题目大意是:输入一个字符串,输出其中第一个不重复的字符;查重时不区分大小写,但是输出时区分大小写。 我的答案 deffirst_non_repeating_letter(string):ifstring:res=[iforiinstringifstring.lower().count(i...
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[Algorithm] 387. First Unique Character in a String 2019-12-13 22:36 −Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0... ...