01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第151题(顺位题号是665)。给定一个包含n个整数的数组,您的任务是通过修改最多1个元素来检查它是否可以变为非递减。如果array [i] <= array [i + 1],且0 <= i <n,则我们定义一个数组是非递减的。例如: 输入:[4,2,3] 输出:true 说明:可以修...
73. 非降序数组(Non-decreasing Array) Alice it 来自专栏 · 算法笔记 一. 题目(medium) 改变数组里的一个值,实现非降序数组,也就是每个数字都比之前的数字大或者相等。二. 思路 判断前两个数字 是否都大于当前的数字,来决定改谁的值。当nums[i-1] > nums[i]时,就再看看是否 nums[i-2] > nums[i]...
We define an array is non-decreasing ifnums[i] <= nums[i + 1]holds for everyi(0-based) such that (0 <= i <= n - 2). Example 1: Input:nums = [4,2,3]Output:trueExplanation:You could modify the first 4 to 1 to get a non-decreasing array. Example 2: Input:nums = [4,2...
Description: Given an array with n integers, your task is to check if it could become non-decreasing by modifying at most 1 element. We define an array is non-decreasing if array[i] <= array[i + 1] holds for every i (1 <= i < n). Example 1: Input: [4,2,3] Output: True ...
Explanation: You can't get a non-decreasing array by modify at most one element. Note: Thenbelongs to [1, 10,000]. 题目标签:Array 题目给了我们一个nums array, 只允许我们一次机会去改动一个数字,使得数组成为不递减数组。可以实现的话,return true;不行的话,return false。
Explanation: You can't get a non-decreasing array by modify at most one element. 1. 2. 3. Note:Thenbelongs to [1, 10,000]. 思路: 本题思路如下: step1:复制数组nums得nums_c step2:遍历数组,当当前值小于前一个值时,对两个数组做删除操作,nums删除当前值,nums_c删除前面一个值 ...
Given an array with n integers, your task is to check if it could become non-decreasing by modifying at most 1 element. We define an array is non-decreasing if array[i] <= array[i + 1] holds for every i (1 <= i < n). Example 1: 代码语言:javascript 代码运行次数:0 运行 AI代...
[i] <= array[i + 1] holds for every i (1 <= i < n)...Example 1: Input: [4,2,3] Output: True Explanation: You could modify the first 4 to 1 to get a non-decreasing...Example 2: Input: [4,2,1] Output: False Explanation: You can't get a non-decreasing array by modi...
Input:[4,2,1]Output:FalseExplanation:You can't get a non-decreasing array by modify at most one element. Note:The n belongs to [1, 10,000]. 首先在Array里面找到逆序的元素,也就是nums[i] > nums[i + 1], 用reversOrder来记录逆序的个数。如果个数超过1,则不可能通过改一个元素就变成正序...
665. Non-decreasing Array 这题看似简单但是AC百分比很低,因为这题有两种情形: 比如5,8,7,9和5,8,1,9都是i = 2的时候发现不满足升序,但是前者需要改变的是7,后者需要改变的是1。 知道了这个道理,代码就很好写了。 publicbooleancheckPossibility(int[]nums){intn=nums.length,count=0;for(inti=0;i+1...