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百度试题 结果1 题目The equation kx^2+kx+3-k=0, where k is a constant, has no real roots.Show that 5k^2-12k0. 相关知识点: 试题来源: 解析 (split)&kx^2-4k(3-k)\&=k^2-12k+4k^2\&=5k^2-12k<0(split) 反馈 收藏
【题目】5 EquatiOnx^2+2x-3=0haS ().(A)no real roots(B)two distinct real roots(C)two equal real rootsD)not sure 相关知识点: 试题来源: 解析 【解析】B 结果一 题目 【题目】5Equation x2+2x-3=0 has().(A)no real roots(B)two distinct real roots(C)two equal real roots(D)not ...
If the equation (x^2 + a|x| + a + 1)(x^2 + (a + 1)|x| + a)= 0 has no real root, then the range of values of a is
the equation x2-2x-m=0 has no real roots and m is a real number,determinewhether the equation x2+2mx+m(m+1)=0 has real roots.14 Given that the equation x2-2x-m=0 has no real roots and m is a real number,determine whether the equation x2+2mx +m(m+1)=0 has real root...
5Equation x2+2x-3=0 has ()(A)no real roots(B)two distinct real roots(C)two equal real roots(D)not sure5 Equation α"+2x-3=0 has( ). (A)no real roots (B) two distinct real roots (C)two equal real roots (D)not sure 答案 5-|||-B优质解答相关...
6If the quadratic equation in one variable x,2x2-(4k+1)x+2k2-1=0,has no real roots,the set of values that k can take is6 If the quadratic equation in one variable.X,2x2-(4k+1)x+2k8-1=0,has no real roots, the set of values that k can take is__ ...
Solution: The real zeros of y = -x2 + x - 1 are those real values of x for which the curve crosses the x-axis, i.e., satisfying: 0==x2+x-1- (1) The discriminant, b2 - 4ac, of Equation (1) is equal to (-1)2 - 4(-1)(-1) = 1 - 4 = -3。 Since the discri...
The real roots of the equation |x|^3-3x^2+3|x|-2=0 are 01:56 The number of positive integral roots of x^(4) + x^(3) - 4 x^(2) + x +... 02:44 If x, y, z are real and distinct, then x^(2) + 4 y^(2) + x + 1 = 0, is 04:51 The number of values of...
5.如图,在解关于x的方程ax+b=0的程序中,横线上应填的内容依次是()(A) x=b/a, “No real root", “The roots areall real numbers(B) x=-b/a, “The roots are all real num-bers", “No real root(C)x=-b/a, “No real root", “The rootsare all real numbers(D) x=b/a, “The...