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Answer to: Find the values for k for which the equation x^2 - 4x + 5k will have no real roots. By signing up, you'll get thousands of step-by-step...
9. The equation x2 + (6k +4)x + 3 = 0, where k is a constant, has no real roots.(a)Show that k satisfies the inequality9k^2+12k+10 (b)Find the range of possible values for k, giving your boundaries as fully simplified surds. 相关知识点: 试题来源: 解析 (a)Uses ...
If the equation x^(2)-x+ m^(2) = 0 has no real roots then m can satisf... 02:37 Find the set of real values of 'm' for which the equation ((x)/(1+x^(2... 02:08 The value of m for which the equation x^(2)-x+m^(2)=0 has no real root... 01:21 The equation...
相关知识点: 试题来源: 解析 14 Since the cquationx^2-2x-m=0has no real roots, △_1=4+4m0 , that is m-1, so A2= -4m 0. Therefore, the equation x2+ 2mx + m(m+1)=0 has two distinct real roots. 反馈 收藏
If alpha,beta are the roots of x^2+p x+q=0a n dgamma,delta are the r... 08:23 Let f(x)=x^2+b x+c ,w h e r eb ,c in Rdot If f(x) is a factor of both... 04:01 If the equation a x^2+b x+c=x has no real roots, then the equation a(a... 02:50 The ...
Find a polynomial equation with real coefficients that has the given roots. Roots: -2, 3, -6 How to determine if a polynomial has real roots? Find a cubic polynomial with real coefficients and roots 2 , 1 8 , and 17 8 . What are all the real and complex roo...
百度试题 结果1 题目The equation kx^2+kx+3-k=0, where k is a constant, has no real roots.Show that 5k^2-12k0. 相关知识点: 试题来源: 解析 (split)&kx^2-4k(3-k)\&=k^2-12k+4k^2\&=5k^2-12k<0(split) 反馈 收藏
To solve the given equations and find the number of roots for each case, we will analyze them step by step.Step 1: Solve the equation \(x^2 \tan x = 1\) for \(x \in (0, 2\pi)\)1. Rearranging the equation gives us \(\tan
$$(A) no real roots (B) two distinct real roots(C) two equal real roots (D) not sure 相关知识点: 试题来源: 解析 5 B 结果一 题目 5Equation x2+2x-3=0 has ()(A)no real roots(B)two distinct real roots(C)two equal real roots(D)not sure5 Equation α"+2x-3=...