Simple, it would be great if this project would support JSON 5 (https://json5.org/), which has both comment support and doesn't choke on trailing commas. 👍 2 robiwano added the kind: enhancement/improvement label May 7, 2020 Owner nlohmann commented May 7, 2020 Duplicate of #34...
Each JSON object has an overhead of one pointer (the maximal size of a union) and one enumeration element (1 byte). The default generalization uses the following C++ data types: std::string for strings, int64_t, uint64_t or double for numbers, std::map for objects, std::vector for ...
我有以下代码(简化): namespace nlohmann { // https://github.com/nlohmann/json/issues/1749#issuecomment-772996219 template <class T> void to_json(nlohmann::json &j, const std::optional<T> &v) { if (v.has_value()) j = *v; else j = nullptr; } template <class T> 浏览10提问于202...
In the nlohmann::json implementation, you interact with two basic containers (json::object,json::array) both have keys that can be easily retrieved or printed. Here is a small example that implements a function to recursively (or not) traverse the JSON object and print the keys and value t...
Add a comment 0 You can use the single include header file.. Now there are two ways to get this header file. One way would be directly downloading the file from the location and using it in your project. Another way would be to clone the entire repo and copy the ...
The parser functions have now an option to ignore//and/* */stylecomments. Though comments are not officially part of the JSON specification (seeherefor a discussion), comment support was a frequently requested feature, and its implementation was much less effort than continuously explaining the la...
JSON for Modern C++ (即为 nlohmann_json)是一个由德国大牛 nlohmann 编写的在 C++ 下使用的 JSON 库; json-for-modern-cpp 只有一个 json.hpp 文件, 但是最低需要 C++11 GCC 4.8.0 以上编译器才能使用;
nlohmann C++库是一个开源的JSON解析库,它提供了简单易用的API,用于读取和操作JSON数据。它支持C++11标准及更高版本,并且具有跨平台的特性。 JSON(JavaScript Object Notation)是一种轻量级的数据交换格式,常用于前后端数据传输和存储。JSON由键值对组成,可以表示复杂的数据结构,包括对象、数组、字符串、数字等。 使用...
使用HTTPS 协议时,命令行会出现如下账号密码验证步骤。基于安全考虑,Gitee 建议 配置并使用私人令牌 替代登录密码进行克隆、推送等操作 Username for 'https://gitee.com': userName Password for 'https://userName@gitee.com': # 私人令牌 nlohmannjson / ChangeLog.md ChangeLog.md 221.88 KB ...
Status:NEW Alias:None Product:Fedora Component:Package Review Version:rawhide Hardware:All OS:Linux Priority:medium Severity:medium Target Milestone:--- Assignee:Nobody's working on this, feel free to take it QA Contact:Fedora Extras Quality Assurance ...