Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2901 Accepted Submission(s): 941 全栈程序员站长 2022/01/17 2200 公平组合游戏-巴什游戏、尼姆游戏和SG函数 游戏 公平组合游戏(Impartral Combinatorial Game)是满足以下特征的一类问题: ...
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 858 Accepted Submission(s): 412 Problem Description Nim is a two-player mathematic game of strategy in which players take turns removing objects from distinct heaps. On each turn, a playe...
gaojie | We have carefully selected several similar problems for you:30313033303830353034 题解: 每一轮允许两会中操作之一:①从一堆石子中取走任意多个②将一堆数量不少于2的石子分成都不为空的两堆。 这个问题可以用SG函数来解决。首先,操作①其实和Nim游戏没什么区别,对于一个石子数为k的点来说,后继可以为...
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2016 Accepted Submission(s): 1048 Problem Description Nim is a two-player mathematic game of strat...Nim or not Nim? HDU - 3032 打表找规律:下面代码里体现了如何打表 在题目的规则下:...
sg[4*k+1]=4*k+1, sg[4*k+2]=4*k+2, sg[4*k+3]=4*k+4, sg[4*k+4]=4*k+3 然后就可以写代码了~ #include<bits/stdc++.h> using namespace std; typedef long long ll; const int N = 1e6 + 10; int getsg(int x){ if(x == 0) return x;//因为0%任何数都为0,将该情...
对于所有的k >= 0,有 sg( 4k+1 ) = 4k+1; sg( 4k+2 ) = 4k+2; sg( 4k+3 )= 4k+4; sg( 4k+4 ) = 4k+3。 #include<bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); int n,t; cin>>t; while(t--){ cin>>n; int x,ans=0; for(int...
sg(n)=n(k=1,k=2)sg(n)=n(k=1,k=2) sg(n)=n+1(k=3)sg(n)=n+1(k=3) 考虑证明: 对于{1,2,3,4,5,6,7,8}{1,2,3,4,5,6,7,8},都是成立的 考虑对于4n,4n+1,4n+2,4n+34n,4n+1,4n+2,4n+3四个归纳 首先,这四个数可以取1∼4n−11∼4n−1中所有数的sgsg值 ...
再推一些,推测得到:对于所有的k >= 0,有 sg( 4k+1 ) = 4k+1;sg( 4k+2 ) = 4k+2;sg( 4k+3 ) = 4k+4;sg( 4k+4 ) = 4k+3。 假设游戏初始时有3堆,分别有2、5和7颗石子。三堆的SG函数值分别为2、5、8,他们的Nim和等于15.所以要走到P状态,就要使得第三堆的SG值变成7,可以将第三对...
Nim or not Nim?Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2564 Accepted Submission(s): 1335 Pro... HDU 3032 Nim or not Nim? (Multi-SG) 题意:普通nim+可以将大于2的一堆石子拆成两堆。 思路:叫做Multi-SG ,也是可以用SG函数...
Nim or not Nim?Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2564 Accepted Submission(s): 1335 Pro... HDU 3032 Nim or not Nim? (Multi-SG) 题意:普通nim+可以将大于2的一堆石子拆成两堆。 思路:叫做Multi-SG ,也是可以用SG函数...