答案【解】(1) y'=(e^(-x))'(x^2-2x+3)+e^(-x)(x^2-2x+3)'=-e^(-x)(x^2-2x+3)+e^(-x)(2x-2)=e^-2 =e^(-x)(-x^2+4x-5) ;2) y'=(xec^2x/a)^2+(cx^2x/a)^2=2secx/a⋯ecx/a⋅tanx/a⋅ rac(aa=2/a(ae^2x/...