ph=10.0的溶液中oh-浓度为1*10^-4,kb=c(nh4+)c(oh-)/c(nh3·h2o)=1.79*10^-5,nh4cl为强电解质,抑制了氨水电离,所以可以忽略弱电解质氨水的电离,又氨水浓度较大,故可忽略nh4cl水解(这就是缓冲溶液的特点),所以 c(nh3·h2o)=16*0.35/1=5旦沪测疚爻狡诧挟超锚.6mol/l,(即用16m氨水350ml) 故c...
缓冲溶液pH计算公式:pH=pKa-lg[c(共轭酸)/c(共轭碱)],Ka是共轭酸的电离常数对于该缓冲体系,共轭酸是NH4+,共轭碱是NH31mol/l NH3-NH4Cl按照题目意思好像是二者浓度均是1mol/l ,所以pH=pKa00分享举报您可能感兴趣的内容广告 2023185玉兔元素传奇_原汁原味_重温经典 185玉兔元素传奇没意思了?那是因为你没玩...
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The pH of buffer ofNH4OH+NH4Cl- type is given by - View Solution 1lit of buffer solution contains0.1mole each ofNH4OHandNH4Cl. What will be thePHof the solution when0.01mole ofHClis added to it [PKbofNH4OH=4.74] View Solution
HYDROCARBON BOOK - MOTIONCHAPTER - HYDROCARBON EXERCISE - Exercise - 4 (Level-II) 15 Videos ISOMERISMBOOK - MOTIONCHAPTER - ISOMERISMEXERCISE - Exercise 4 26 Videos Similar Questions The pH of basic buffer mixtures is given by : pH=pKa+log([Base][Salt]) , whereas pH of acidic buffer mix...