百度试题 结果1 题目Cau 77: Mot nguyen ham cua ham so y=sin 3x A A. -1/3cos3x B. -3cos3x C. 3cos3x D. fcos3x 相关知识点: 试题来源: 解析 A 反馈 收藏
百度试题 结果1 题目Cau 10: Nguyen ham cua ham so f(x)=sin3x1 : A A. ∫f(x)dx=-1/3cos3x+C B. ∫f(x)dx=1/3cos3x+C C. ∫f(x)dx=-1/3cosx+C D. ∫f(x)dx=-cos3x+C 相关知识点: 试题来源: 解析 A 反馈 收藏
试题来源: 解析 D- Hướng dẫn giảiPhương pháp giải:Sử dụng công thức nguyên hàm ∫cos(ax+b)dx=1/asin(ax+b)+cGiải chi tiết:Ta có ∫cos(3x-2)dx=1/3sin(3x-2)+CChọn D 反馈 收藏 ...
解析 Ta có:m^3x^3-\frac(-\frac(421)(x^4)+\frac(24)(4x^4)Suy ra: sin^3xcos^3∴1/a+b/a+b/b+(2b+ab)/(ab+b+c+b+1⋅(b+a)/(1-a)=((a+b)/(a+b)+b/a+\frac(Vậy I=-3/4∫sin2xdx=3/8cos2x+C 反馈 收藏 ...
Cau 26: Tim nguyen ham cua ham so: f(x)=sin^2xcos^3xA A.(sin^3x)/3-(sin^5x)/5+ C B. S3 5s (sin^5x)/5-(sin^3x)/3+ C C (cos^3x)/3-(cos^5x)/5+ C D . (cos^5x)/5-(cos^3x)/3+C553 相关知识点: 试题来源: 解析 A ...
百度试题 结果1 题目 Cau 42: Nguyen ham cua f(r) = r cos z la A. F(x)=-xsinx-cosx+ C . B. F(x)=xsinx+cosx+C F(x)=xsinx-cosx+ C . D. F(x)=-xsinx+cosx+C 相关知识点: 试题来源: 解析 B 反馈 收藏
百度试题 结果1 题目 Cau 77: Mot nguyen ham cua ham so: y=cos5x.cosx la: A A. cos6x B.1/2(1/6sin6x+1/4sin4x) . sin6x D.-1/2((sin6x)/6+(sin4x)/4) 相关知识点: 试题来源: 解析 A 反馈 收藏
Cau 9. Tim ho nguyen ham cua ham so f(x)=xcosx⋅D A. ∫f(x)dx=xsinx-cosx+C B.. ∫f(x)dx=-xsinx-cosx+C C. ∫f(x)dx=-xsinx+cosx+(=-xsin x+ cosx+ C D. ∫f(x)dx=xsinx+cosx+(= xsin x + cos x+ C 相关知识点: 试题来源: 解析...
Cau 26: Tim nguyen ham F(x)=fsin2xdx A A. F(x)=-1/2cos2x+ C . B. F(x)=2cos2x+C C. F(x)=-2cos2x+ C . D. F(x)=1/2cos2x+ C . 相关知识点: 试题来源: 解析 ATa có F(x)=∫sin2xdx=-1/2cos2x+C 反馈 收藏 ...
SofianeHamlaoui/CVE-2022-0492-Checker puckiestyle/CVE-2022-0492 chenaotian/CVE-2022-0492 CVE-2022-0529 (2022-02-09) A flaw was found in Unzip. The vulnerability occurs during the conversion of a wide string to a local string that leads to a heap of out-of-bound write. This flaw allow...