leetcode算法:Next Greater Element I You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. The Next Greater Number of a number x in nums1 i...
For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. For number 1 in the first array, the next greater number for it in the second array is 3. For number 2 in the first array, there is no next greater number for it...
LeetCode题目:503. Next Greater Element II Given acircular array (the next element of the last element is the first element of the array),print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the...
题目地址:https://leetcode.com/problems/next-greater-node-in-linked-list/ 题目描述 We are given a linked list withheadas the first node. Let’s number the nodes in the list:node_1, node_2, node_3, ...etc. Each node may have a next larger value: fornode_i,next_larger(node_i)is...
The number 2 can't find next greater number; The second 1's next greater number needs to search circularly, which is also 2. Note: The length of given array won't exceed 10000. 这道题是之前那道Next Greater Element I的拓展,不同的是,此时数组是一个循环数组,就是说某一个元素的下一个较...
Can you solve this real interview question? Next Greater Numerically Balanced Number - An integer x is numerically balanced if for every digit d in the number x, there are exactly d occurrences of that digit in x. Given an integer n, return the smallest
leetcode503. Next Greater Element II 题目要求 Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next ...
leetcode 503.下一个更大元素 ii #栈鱼沙 97 播放 · 0 弹幕 【300题刷题挑战】leetcode力扣225 用队列实现栈 mystack 第一百三十九题 | 栈和队列 soulbit花云田 115 播放 · 0 弹幕 leetcode503. next greater element ii 【m】用户正在刷题磕cp 29 播放 · 0 弹幕 【300题刷题挑战...
借助stack,遍历nums,如果stack为空或者nums[stack[-1]] >= nums[i],将i压入stack,表示nums[i]还未找到它的下一个greater element。当nums[stack[-1]]<nums[i]时,表示nums[i]即为nums[stack[-1]]的下一个较大元素,因此从stack中取出该索引index,将nums[i]存入result[index]中。由于nums是循环的,因此...
1 读题:LeetCode 496E 下一个最大元素 2 解题思路 单调栈(栈底最大)的作用在于: 保持栈底始终是一个全栈最大的数值; 目标原来过来,和栈顶的元素对比 (此时要求栈非空),如果栈顶的元素比它大,那么就找到了一个离它最近的、且比它大的元素;