这个题和之前的503. Next Greater Element II做法一样的,都是使用一个单调递减栈保存每个数字的下标。首先,把链表遍历一遍,转化成数组问题。然后遍历数组,需要维护单调递减栈,每个元素的位置都要往栈里面放,放之前先把栈里面小于该元素的全部弹出。如果遇到了一个数字n比栈顶元素stack[-1]为下标的数字更大时,...
这个题和之前的503. Next Greater Element II做法一样的,都是使用一个单调递减栈保存每个数字的下标。 首先,把链表遍历一遍,转化成数组问题。 然后遍历数组,需要维护单调递减栈,每个元素的位置都要往栈里面放,放之前先把栈里面小于该元素的全部弹出。 如果遇到了一个数字n比栈顶元素stack[-1]为下标的数字更大时...
nums.add(node.val); res=newint[nums.size()];//use stack to find next greater elementfor(inti=0; i<nums.size(); i++) {//once find a greater num, it will check all previous numbers in stackwhile(!stack.isEmpty() && nums.get(stack.peek()) <nums.get(i)) res[stack.pop()]=...
Can you solve this real interview question? Next Greater Element I - The next greater element of some element x in an array is the first greater element that is to the right of x in the same array. You are given two distinct 0-indexed integer arrays num
Can you solve this real interview question? Next Greater Element II - Given a circular integer array nums (i.e., the next element of nums[nums.length - 1] is nums[0]), return the next greater number for every element in nums. The next greater number of
题目描述: LeetCode 496. Next Greater Element I You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums
public int[] nextGreaterElement(int[] findNums, int[] nums) { if (findNums == null || nums == null) { return null; } int findLength = findNums.length; int numsLength = nums.length; int[] result = new int[findLength];
LeetCode-Next Greater Element I Description: You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2....
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
leetcode556. Next Greater Element III 题目要求 Given a positive32-bitintegern, you need to find the smallest32-bitinteger which has exactly the same digits existing in the integernand is greater in value than n. If no such positive32-bitinteger exists, you need to return -1....