想到了用哈希表存这个数的位置,但是没有想到可以直接用哈希表存next great,用栈存还没找到的数,没遍历一个数就考察栈中的元素小,小的话,这个数就是栈中数的next great,栈中的数肯定是下大上小。 publicint[] nextGreaterElement(int[] nums1,int[] nums2) {/*通过map建立当前元素和其next grea
Github 同步地址: https://github.com/grandyang/leetcode/issues/1019 类似题目: Next Greater Element I Next Greater Element II Next Greater Element III 参考资料: https://leetcode.com/problems/next-greater-node-in-linked-list/ https://leetcode.com/problems/next-greater-node-in-linked-list/discuss...
这个题和之前的503. Next Greater Element II做法一样的,都是使用一个单调递减栈保存每个数字的下标。 首先,把链表遍历一遍,转化成数组问题。 然后遍历数组,需要维护单调递减栈,每个元素的位置都要往栈里面放,放之前先把栈里面小于该元素的全部弹出。 如果遇到了一个数字n比栈顶元素stack[-1]为下标的数字更大时...
Can you solve this real interview question? Next Greater Element II - Given a circular integer array nums (i.e., the next element of nums[nums.length - 1] is nums[0]), return the next greater number for every element in nums. The next greater number of
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
public int[] nextGreaterElement(int[] findNums, int[] nums) { if (findNums == null || nums == null) { return null; } int findLength = findNums.length; int numsLength = nums.length; int[] result = new int[findLength];
LeetCode 556. Next Greater Element IIIGiven a positive 32-bit integer n, you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer n and is greater in value than n. If no such positive 32-bit integer exists, you need to return -1....
LeetCode-Next Greater Element I Description: You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2....
Next Greater Element I ...[LeetCode] 496. Next Greater Element I 题目内容 https://leetcode-cn.com/problems/next-greater-element-i/ 给定两个没有重复元素的数组 nums1 和 nums2 ,其中nums1 是 nums2 的子集。找到 nums1 中每个元素在 nums2 中的下一个比其大的值。 ......
leetcode556. Next Greater Element III 题目要求 Given a positive32-bitintegern, you need to find the smallest32-bitinteger which has exactly the same digits existing in the integernand is greater in value than n. If no such positive32-bitinteger exists, you need to return -1....