Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search ci...
题目地址:https://leetcode.com/problems/minesweeper/description/ 题目描述 Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first grea...
Leetcode 503. Next Greater Element II 1. Description 2. Solution **解析:**Version 1,由于元素不是唯一的,需要循环查找,因此先将nums复制一遍,通过循环每次都查找当前元素之后的n-1位数字。Version 2通过使用栈来寻找满足条件的结果,栈中保持是数字的索引位置,由于需要循环查找,因此需要查找两次nums,并且第二...
LeetCode:Next Greater Element II 503. Next Greater Element II Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traver...
Given a circular integer arraynums(i.e., the next element ofnums[nums.length - 1]isnums[0]), returnthenext greater numberfor every element innums. Thenext greater numberof a numberxis the first greater number to its traversing-order next in the array, which means you could search circul...
/* * @lc app=leetcode id=503 lang=cpp * * [503] Next Greater Element II * * https://leetcode.com/problems/next-greater-element-ii/description/ * * algorithms * Medium (51.85%) * Likes: 791 * Dislikes: 48 * Total Accepted: 57.8K * Total Submissions: 111.2K * Testcase Example:...
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search ci...
LeetCode题目:503. Next Greater Element II Given acircular array (the next element of the last element is the first element of the array),print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the...
借助stack,遍历nums,如果stack为空或者nums[stack[-1]] >= nums[i],将i压入stack,表示nums[i]还未找到它的下一个greater element。当nums[stack[-1]]<nums[i]时,表示nums[i]即为nums[stack[-1]]的下一个较大元素,因此从stack中取出该索引index,将nums[i]存入result[index]中。由于nums是循环的,因此...
leetcode503. Next Greater Element II 题目要求 Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next ...