https://leetcode.cn/problems/next-greater-element-ii 给定一个循环数组 nums ( nums[nums.length - 1] 的下一个元素是 nums[0] ),返回 nums 中每个元素的 下一个更大元素 。 数字x 的 下一个更大的元素 是按数组遍历顺序,这个数字之后的第一个比它更大的数,这意味着你应该循环地搜索它的下一个更...
LeetCode 503. Next Greater Element II (下一个更大元素 II) 题目 链接 https://leetcode-cn.com/problems/next-greater-element-ii/ 问题描述 给定一个循环数组 nums ( nums[nums.length - 1] 的下一个元素是 nums[0] ),返回 nums 中每个元素的 下一个更大元素 。 数字x 的 下一个更大的元素 是...
Leetcode 503. Next Greater Element II 1. Description 2. Solution **解析:**Version 1,由于元素不是唯一的,需要循环查找,因此先将nums复制一遍,通过循环每次都查找当前元素之后的n-1位数字。Version 2通过使用栈来寻找满足条件的结果,栈中保持是数字的索引位置,由于需要循环查找,因此需要查找两次nums,并且第二...
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/* * @lc app=leetcode id=503 lang=cpp * * [503] Next Greater Element II * * https://leetcode.com/problems/next-greater-element-ii/description/ * * algorithms * Medium (51.85%) * Likes: 791 * Dislikes: 48 * Total Accepted: 57.8K * Total Submissions: 111.2K * Testcase Example:...
第二个 1 的下一个最大的数需要循环搜索,结果也是 2。 注意: 输入数组的长度不会超过 10000。 详见:https://leetcode.com/problems/next-greater-element-ii/description/ C++: classSolution{public:vector<int>nextGreaterElements(vector<int>&nums){intn=nums.size();vector<int>res(n,-1);for(inti=0...
稍作简化,如下: classSolution{public:vector<int>nextGreaterElements(vector<int>&nums){stack<int>s;intn=nums.size();vector<int>res(n,-1);for(inti=0;i<2*n;i++){intnum=nums[i%n];while(!s.empty()&&num>nums[s.top()]){res[s.top()]=num;s.pop();}if(i<n)s.push(i);}retur...
Q503 Next Greater Element II Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, ...
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search ci...
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search ci...