申请一个 长度为strlen（s）+1的 连续char内存~ 并且ps指向内存的首地址~
因为strlen是计算字符串有多少字符的,不包括结束符”\0“,所以加一。如"abc",占四个字节,strlen的值是3 //释放实例自身已有内存delete[] m_pData; m_pData=NULL; //在删除自身内存以后在重新new一个长度为len+1的字符数组,类似拷贝构造函数intlen=strlen(str.m_pData); m_pData=newchar[len+1]; strc...
这个是c语言传下来的特性,在 C 语言中,字符串是以空字符做为终止标记(结束符)的。所以,C 语言字符串的最后一个字符一定是 \0。strlen 函数返回的是字符串的实际长度(所以不包括结尾的 \0 终止符)。所以为了保证有足够的空间存储所有字符,我们需要在额外 +1。如"abc",占四个字节,strlen的值是3...
给length字符串在堆上分配内存，其长度是字符串str1长度和str2长度的和，最后加1是因为字符串要以‘\0’结尾
结果1 题目char* f(char *s){int n=strlen(s);char* r=new char[n+1];for(int i=0; iif(s[i]>='a' && s[i]<='z') r[i]=s[i]-'a'+'A';else r[i]=s[i];r[n]=’\0’;return r;}函数功能: 相关知识点: 试题来源: 解析 根据参数s所指向的字符串,生成一个由r所指向...
strlen求的是字符串长度，刚开始没初始化，所以是不确定的。如果你用sizeof的话就会是18了。
char* msg1 =newchar[2]; len = strlen(msg1); cout<<len; output: 14 What? shouldn't it be 2 since Ive only declared an array of lenght 2? Last edited onFeb 2, 2012 at 5:29pm Feb 2, 2012 at 5:49pm dolphin spa(19)
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That example may have been overreduced, this one was done more manually but I can verify that GCC and Clang 17.0.1 do not warn whereas current trunk does. typedefunsigned short__u16;typedef__u16__le16;typedefunsigned longsize_t;structcifs_ses{char*user_name; };structshash_desc; __attrib...
C++程序运行出错,有好多乱码“葺葺葺葺葺葺葺葺?”,求救~#include #include class MyString{public:\x05MyString()\x05{\x05\x05str=0;\x05}\x05MyString(const char* rhs)\x05{\x05\x05str=new char[strlen(rhs)+1];\x05\x05for(int i=0;istr);