Python | Nested if else example: Here, we are implement a program, it will input three numbers and find the largest of three numbers. By Pankaj Singh Last updated : December 20, 2023 Problem statementInput three integer numbers and find the largest of them using nested if else in python...
When we run the program the output will be: 2 is less than 5 This statement is always executed. The expression number < 5 will return true, hence the code inside if block will be executed. Ternary operator in C# provides a shortcut for C# if...else statement. C# if...else if (if...
Python If Else Condition In the example above, Python executes the print statement if the condition is satisfied. However, it does not run any code if the condition is false. In this case, we can use theif-elseblock to evaluate the condition and run the else block code if the condition ...
If (year % 4 == 0 && (year % 400 == 0 || year % 100 != 0)){ printf("%d is a leap year", year); } else{ printf("%d is not a leap year", year); } With nested if statements in C, we can write structured and multi-level decision-making algorithms. They simplify coding...
This section describes nested 'if-then-else' statements, where an 'if-then-else' statement contains another 'if-then-else' statement.
// Swift program to demonstrate the// nested if statementvar num1:Int=10; var num2:Int=30; var num3:Int=20;if(num1>num2) {if(num1>num3) { print("Num1 is largest number"); }else{ print("Num3 is largest number"); } }elseif(num2>num3) { print("Num2 is largest number"...
String engineType;voidsetEngine(){// Accessing the carType property of Carif(Car.this.carType.equals("4WD")){// Invoking method getCarName() of Carif(Car.this.getCarName().equals("Crysler")) {this.engineType ="Smaller"; }else{this.engineType ="Bigger"; ...
在这种情况下,您可以使用嵌套if 构造。 在一个嵌套的if构造,你可以有一个if...elif...else在另一个内部构建if...elif...else构造。 句法 嵌套的 if...elif...else 构造的语法可能是 - if expression1: statement(s) if expression2: statement(s) elif expression3: statement(s) else statement(...
} else if (!page.equals(other.getPage())) return false; if (service != other.getService()) return false; return true; } } Solution 3: This class is highly versatile and allows for infinite nesting. It also permits the addition of extra fields and modification of the HashMap types. ...
for i in range(2, number//2): # rule 2: shouldn't have any positive divisor # order than 1 and itself. if(number % i) ==0: return False return True else: return False if __name__ == '__main__': number = int(input("Enter number to check if it's prime: ")) ...