When sodium hydroxide (NaOH) reacts with an acid, it undergoes a neutralization reaction, resulting in the formation of a salt and water. This reaction is commonly referred to as acid-base neutralization. The reaction can be represented by the following general equation: ...
An acid-base reaction is a type of chemical process between an acid and a base where the hydrogen ion of the acid is transferred to the basic substance. This reaction is also known as a neutralization reaction, where the product formed is commonly in the form of salt. These rea...
Solvation of acid, base, and salt is ubiquitously important to all subject areas in chemistry, health care and life science. However, fine resolution of the solvation dynamics, solute-solvent molecular interactions, and solute capability of transforming the hydrogen bond (O:H O, or HB) and ...
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<p>To determine which among the given options will not react with sodium hydroxide (NaOH) or which is not an acid salt, we need to analyze the structures of the compounds provided in the question. An acid salt is a salt that contains an acidic hydrogen a
In a neutralization reaction, a strong acid mixes with a strong base to form a salt and water as shown below: NaOH + HCl = H2O + NaCl. How many grams of NaOH are required to neutralize 100 g of HCl? Note: Problem solv...
it is not used for shaving, it is used for soap production. oil and fat triglycerides react with sodium hydroxide to form fatty acid glycerol and sodium salts, the latter being the soaps. the extraction of excess sodium hydroxide is done with great caution because it is very caustic. also,...
Neutralization reactions occur when an acid and a base react, forming water from the hydrogen ion and hydroxide ion, and a salt. Neutralization reactions can be acidic, neutral, or basic in nature, depending on the strengths of the acid and base involved i...
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The pH was found to be 4.92 .What is Ka of the acid ? Video Solution Text SolutionVerified by Experts At the end point, m.e. (or millimoles) of the salt produced =m.e. of NaOH =0.1×36.12 =3.612 Since salt formed will be uniunivalent and so for such salts m.m.=m....