01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第136题(顺位题号是590)。给定一个n-ary树,返回其节点值的后序遍历。例如,给定一个3-ary树: 1 / | \ 3 2 4 / \ 5 6 其后序遍历结果为:[5,6,3,2,4,1]。 注意:递归解决方案是微不足道的,你可以用迭代的方式做吗? 本次解题使用的开发...
classSolution {public: vector<int> postorder(Node*root) {if(!root)return{}; vector<int>res;if(!root->children.empty()){ vector<Node*>temp=root->children;for(inti=0;i<temp.size();++i){ vector<int> t=postorder(temp[i]); res.insert(res.end(),t.begin(),t.end()); } } res.p...
[LeetCode] 590. N-ary Tree Postorder Traversal Given an n-ary tree, return thepostordertraversal of its nodes' values. Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples). Follow up: Recursive solut...
https://leetcode.com/problems/n-ary-tree-preorder-traversal/ 题目: Given an n-ary tree, return thepreordertraversal of its nodes' values. Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples). Follow...
leetcode429. N-ary Tree Level Order Traversal 题目要求 代码语言:javascript 复制 Given an n-ary tree,returnthe level order traversalofits nodes' values.(ie,from left to right,level by level).For example,given a3-ary tree: 代码语言:javascript...
Solution{public:vector<int>postorder(Node*root){vector<int>ret;if(!root)returnret;stack<Node*>s;s.push(root);Node*cur;while(!s.empty()){cur=s.top();s.pop();ret.insert(ret.begin(),cur->val);for(inti=0;i<cur->children.size();++i){if(cur->children[i])s.push(cur->children...
Binary Tree Traversal Binary Tree Reconstruction(leetcode可用) Polish Notation / Reverse Polish Notation N-ary Tree 什么是树(Tree),树的概念是什么 https://www.geeksforgeeks.org/binary-tree-set-1-introduction/www.geeksforgeeks.org/binary-tree-set-1-introduction/ ...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/find-root-of-n-ary-tree 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 2. 解题 把每个节点及其直接连接的子节点的值进行异或,题目说值无重复 这样根节点只运算了1次,其余节点运算了2次(异或偶数次抵消了) ...
LeetCode题解之N-ary Tree Postorder Traversal 1、题目描述 2、问题分析 递归。 3、代码 1vector<int> postorder(Node*root) {2vector<int>v;3postNorder(root, v);4returnv;5}67voidpostNorder(Node *root, vector<int> &v)8{9if(root ==NULL)10return;11for(auto it = root->children.begin()...
Given an n-ary tree, return the postorder traversal of its nodes' values. 题目分析及思路 题目给出一棵N叉树,要求返回结点值的后序遍历。可以使用递归的方法做。因为是后序遍历,所以最后加入根结点的值。 python代码 """ # Definition for a Node. ...