题目地址:https://leetcode.com/problems/n-queens-ii/description/ 题目描述: The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-queens puzzle. Each solution conta...
classSolution(object):deftotalNQueens(self,n):""":type n:int:rtype:int""" self.n=n self.result=0columns=[-1foriinrange(n)]#[-1,-1,-1,-1]self.solve(columns,0,self.result)returnself.result defis_valid(self,columns,row,col):# print columns,'hang',row,'lie',colforrinrange(r...
classSolution:defsolveNQueens(self, n: int) ->List[List[str]]: board= [['.'] * nfor_inrange(n)]#建立棋盘二维的res =[]defcheck(board,row, col):#判断同一列是否冲突foriinrange(len(board)):ifboard[i][col] =='Q':returnFalse#判断左上角是否冲突i = row -1j= col -1whilei>=0...
代码: classSolution:#@return a list of lists of stringdefsolveNQueens(self, n):defcheck(k, j):#check if the kth queen can be put in column j!foriinrange(k):ifboard[i]==jorabs(k-i)==abs(board[i]-j):returnFalsereturnTruedefdfs(depth, valuelist):ifdepth==n: res.append(valueli...
所以Problem 51 的 Python 代码如下: def NQueens(queenList,line): # 递归函数 # 当行数等于皇后数量时,记录结果 if line == queenNum: temp = [] for i in range(queenNum): s = '' for j in range(queenNum): if [i,j] in queenList: ...
class Solution(object): def __init__(self): self.count = 0 def totalNQueens(self, n):...
class Solution: def solveNQueens(self, n: int) -> List[List[str]]: board = [['.'] * n for _ in range(n)]#建立棋盘二维的 res = [] def check(board,row, col): #判断同一列是否冲突 for i in range(len(board)): if board[i][col] == 'Q': ...
使用python实现的代码如下：class Solution: def NQueens(self, n): self.re = [] se...
Leetcode 51. N皇后问题(N Queens) Python解法 题目描述n皇后问题研究的是如何将n个皇后放置在n×;n的棋盘上,并且使皇后彼此之间不能相互攻击。上图为8皇后问题的一种解法。给定一个整数n,返回所有不同的n皇后问题的解决方案。每一种解法包含一个明确的n皇后问题的棋子放置方案,该方案中‘Q’和‘.’分别代表...
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. Anwser 1: O(n^3) based-on Row 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution { public: bool check(int row, int* colArray) { for (int i = 0...