但是Hackerrank调试器在解释这个错误时非常糟糕，所以我怀疑我的理解。无论如何，这是另一种不使用向量的...
You can iterate over all possible gcds and for each check if there exist two or more numbers divisable by it (and if there are, choose two largest). If you do it in way like this: for (int gcd = 1; gcd < m; gcd++) { for (int i = gcd; i < m; i += gcd) { ... it...
When I did the study plan, I used 2 languages for most of it: C and Python C: Very low level. Allows you to deal with pointers and memory allocation/deallocation, so you feel the data structures and algorithms in your bones. In higher-level languages like Python or Java, these are hi...
BFS and DFS - know their computational complexity, their tradeoffs, and how to implement them in real code When asked a question, look for a graph-based solution first, then move on if none. MIT(videos): Breadth-First Search Depth-First Search Skiena Lectures - great intro: CSE373 2012 ...