UPDATE users SET status = '退休' WHERE age > 30; 子查询更新 代码语言:txt 复制 UPDATE table_name SET column1 = (SELECT new_value FROM another_table WHERE condition) WHERE condition; 例如,根据另一个表中的数据更新当前表中的某个字段: ...
http://stackoverflow.com/questions/6393763/fast-cross-table-update-with-mysql http://stackoverflow.com/questions/11709043/mysql-update-column-with-value-from-another-table
INSERT INTO sales_reps(id, name, salary, commission_pct) SELECT employee_id, last_name, salary, commission_pct FROM employees WHERE job_id LIKE '%REP%'; 2. 更新数据 使用UPDATE 语句更新数据。语法如下: UPDATE table_name SET column1=value1, column2=value2, … , column=valuen [WHERE cond...
UPDATE t_student SET valueName_1 = newVAl,valueName_2 = newVal WHERE condition1 && condition2 --全部对所有数值全部改完 UPDATE t_student SET valueName_1 = newVal ,valueName_2= newVal; 1. 2. 3. 4. 5. 6. 查 --查询表所有数据 SELECT * FROM t_student; -- 查询指定列 SELECT val...
status (\s) Get status information from the server. --获得状态信息 system (\!) Execute a system shell command. --执行系统命令 tee (\T) Set outfile [to_outfile]. Append everything into given outfile. --操作结果输出到文件 use (\u) Use another database. Takes database name as argument...
-- 执行更新操作UPDATE your_table SET your_column = 'new_value' WHERE your_condition;COMMIT;-- 事务2START TRANSACTION;SELECT * FROM your_table WHERE your_condition FOR UPDATE; -- 会等待事务1释放锁-- 执行更新操作UPDATE your_table SET your_column = 'another_value' WHERE your_condition;COMMIT...
匹配列前缀(Match a column prefix):例如,你可以利用索引查找last name以J开始的人,这仅仅使用索引中的第1列。 匹配值的范围查询(Match a range of values):可以利用索引查找last name在Allen和Barrymore之间的人,仅仅使用索引中第1列。 匹配部分精确而其它部分进行范围匹配(Match one part exactly and match a ...
I have two tables verkope and sleutelwoorde. Sleutelwoorde has a column called sleutelwoordeproduk. I want to update verkope's kleur column from sleutelwoorde's kleur column where a substring of produk is contained in sleutelwoordeproduk with kleur. I am using the following : ...
UPDATE my_table SET my_column = (SELECT my_value FROM my_table WHERE condition) WHERE another_condition; 这个错误的原因是MySQL不允许在同一个查询中同时选择和更新同一个表。为了解决这个问题,你可以尝试以下几种方法:方法一:使用临时表你可以将选择操作的结果存储在一个临时表中,然后在更新操作中使用这个...
However I cannot figure out how to update verkope2 (column Tipe) from sleutelwoorde (column Tipe) with the selected fields. My create statement for the sleutel woorde : CREATE TABLE `sleutelwoorde` ( `Woorde` text, `Tipe` text, `Kleur` text ...