MySQL 5.7.8及之后的版本支持原生JSON格式，允许在数据库表中直接存储和操作符合JSON格式的数据。这种原...
'Alice','{"status": "active"}');INSERTINTOusersVALUES(2,'Bob','{"status": "pending"}');INSERTINTOusersVALUES(3,'Charlie','{"status": "inactive"}');SELECT*FROMusersWHEREJSON_UNQUOTE(JSON_EXTRACT(details,'$.status'))IN('active','pending');...
mysql> select JSON_TYPE('[1,2,3'); ERROR 3141 (22032): Invalid JSON text in argument 1 to function json_type: "Missing a comma or ']' after an array element." at position 6. mysql> select JSON_TYPE('{"apple":"food}'); ERROR 3141 (22032): Invalid JSON text in argument 1 to...
参数2 Value值, 参数3 Key值[语法格式:'$.keyname'])SELECTJSON_CONTAINS(@j,@j2,'$.a');--查询的是JSON对象的a属性,a属性的值是1,符合函数的包含条件,所以返回1表示结果TRUESELECTJSON_CONTAINS(@j,@j2,'$.b');--查询的
SELECTJSON_VALUE(inverstor_info_json,'$.inverstorScore.addrFlagScore')FROM`t_customer_score`WHEREid=47178;SELECTJSON_QUERY(inverstor_info_json,'$.famous')FROM`t_customer_score`WHEREid=47178; inverstor_info_json存储文本格式举例如下: {"addrExist":"addrExist_1","addrFlag":"addrFlag_1","adj...
mysql> create table t(c1 json);Query OK, 0 rows affected (0.09 sec)mysql> insert into t values('{ "name":"John", "age":30, "city":"New York"}');Query OK, 1 row affected (0.01 sec)mysql> select c1->"$.age" from t;
01 sec) mysql> insert into t values('{"id": 87, "name": "carrot"}'); Query OK, 1 row affected (0.01 sec) 也可使用函数,常用的有 JSON_ARRAY() 和 JSON_OBJECT(),前者用于构造 JSON 数组,后者用于构造 JSON 对象。如, mysql> select json_array(1, "abc", null, true,curtime()); ...
JSON_INSERT()可以添加新值,但它不会替换已存在的值。 mysql> select json_insert(@json, '$[1].attr[0]', 2, '$[2]', "pear"); +---+ | json_insert(@json , '$[1].attr[0]', 2 , '$[2]', "pear") | +---+ | ["apple", {"attr...
new LambdaQueryChainWrapper<>(baseMapper) .select(Test::getRoleName) .list(); 对应执行的 sql 如下 SELECT roles ->> '$[*].name' AS roleName FROM json_test 这种方法可以在 select 中用MySql 里的函数,比如常用的 SUM、MAX、COUNT 等 @TableField(value = "SUM(money)", insertStrategy = Field...
在某些场景下,Json类型简直是福音。...假定表结构如下: id data 1 {'name':'李磊','age':28} 2 {'name':'张磊','age':38} 一维json查询利用函数 select * from user...)= 28; -- or selectjson_extract(data,'$.age') as age from user having age =28; 二维json查询id data 1 [{...(...