· 错误:1064 SQLSTATE: 42000 (ER_PARSE_ERROR) 消息:在行%d上,%s靠近'%s'。 · 错误:1065 SQLSTATE: 42000 (ER_EMPTY_QUERY) 消息:查询为空。 · 错误:1066 SQLSTATE: 42000 (ER_NONUNIQ_TABLE) 消息:非唯一的表/别名:'%s' · 错误:1067 SQLSTATE: 42000 (ER_INVALID_DEFAULT) 消息:关于'%s'的...
Re: Parse error: syntax error, unexpected T_VARIABLE in /usr/home/www/inventory/verify_parts.php on line 96 Peter Brawley March 06, 2009 11:16AM Sorry, you can't reply to this topic. It has been closed.Content reproduced on this site is the property of the respective copyright holde...
错误号:1064; 符号: ER_PARSE_ERROR; SQLSTATE: 42000 消息:%s在第%d行靠近“%s” 错误号:1065; 符号: ER_EMPTY_QUERY; SQLSTATE: 42000 消息:查询为空 错误号:1066; 符号: ER_NONUNIQ_TABLE; SQLSTATE: 42000 消息:不是唯一的表/别名:'%s' 错误号:1067; 符号: ER_INVALID_DEFAULT; SQLSTATE: 4200...
Parse error: syntax error, unexpected T_VARIABLE...on line 7. The simple code is as follows: <? php $pwd = $_POST['password']; $dbn = $_POST['dbname']; $hnm = $_POST['hostname']; $link_id = mysql_connect($hnm,$dbn,$pwd); // this is line 7 where I ...
Most likely, you have hit a bug, but this error can also be caused by malfunctioning hardware. Thread pointer: 0x7f55ac0008c0 Attempting backtrace. You can use the following information to find out where mysqld died. If you see no messages after this, something went ...
port); });ERROR : 1:列名long不能是MySQL的关键字 2:字段long未设置字段描述，不符合命名规范 ...
· 错误:1064 SQLSTATE: 42000 (ER_PARSE_ERROR) 消息:在行%d上,%s靠近'%s'。 · 错误:1065 SQLSTATE: 42000 (ER_EMPTY_QUERY) 消息:查询为空。 · 错误:1066 SQLSTATE: 42000 (ER_NONUNIQ_TABLE) 消息:非唯一的表/别名:'%s' · 错误:1067 SQLSTATE: 42000 (ER_INVALID_DEFAULT) ...
你贴出来的代码没有错误，错误在C:\Apache24\htdocs\dbwrap.php 文件的第 35行，请粘贴那个文件，并指出35行的位置（粘贴上来行号可能改变）。
·错误:1064 SQLSTATE: 42000 (ER_PARSE_ERROR) 消息:在行%d上,%s靠近'%s'。 ·错误:1065 SQLSTATE: 42000 (ER_EMPTY_QUERY) 消息:查询为空。 ·错误:1066 SQLSTATE: 42000 (ER_NONUNIQ_TABLE) 消息:非唯一的表/别名:'%s' ·错误:1067 SQLSTATE: 42000 (ER_INVALID_DEFAULT) ...
Parse error: syntax error, unexpected T_VARIABLE in C:\wamp\www\database\tables.php on line 6 can ny one resolve it plz. here is the script <?php include "./common_db.inc"; $dbname = "sample_db"; $user_tablename = 'user' ...