next_day函数是MySQL内置函数之一,用于获取指定日期之后的第一个满足条件的星期几。它的语法如下: NEXT_DAY(date,day_of_the_week) 1. 其中,date是待查询的日期,day_of_the_week是星期几的英文缩写(如’Mon’, ‘Tue’, ‘Wed’, ‘Thu’, ‘Fri’, ‘Sat’, ‘Sun’)。 使用next_day函数的示例 下面...
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not 取反 update t_student set s_age = s_age - 2 where s_class_id not in(1,3,4);判断为null 注意: 不是用的=null在mysql中null和任意的值比较都是false 而是使用 is null,update t_student set s_age = 50 where s_age is null and s_class_id=1;取反 update t_student set s_age =...
ADD_MONTHS(date,i):select add_months(sysdate,3),add_months(sysdate,-3) from dual; NEXT_DAY(date,char):select next_day(sysdate,'星期一') from dual; LAST_DAY(char):select last_day(sysdate) from dual; MONTHS_BETWEEN(char1,char2):计算2个日期之间间隔的月份 select months_between('20-5月...
SELECT DATE_ADD(NOW(), INTERVAL 1 DAY) AS next_day; 常见问题及解决方法 问题1:日期时间格式不正确 原因:可能是输入的字符串不符合指定的格式。 解决方法: 代码语言:txt 复制 SELECT STR_TO_DATE('2023/10/05 14:30:00', '%Y-%m-%d %H:%i:%s') AS parsed_datetime; ...
day_of_month=DATE_FORMAT( DATE, "%d" ), day_of_year=DATE_FORMAT( DATE, "%j" ), previous_day=DATE_ADD(DATE, INTERVAL-1DAY), next_day=DATE_ADD(DATE, INTERVAL1DAY), weekend=IF( DATE_FORMAT( DATE, "%W" )IN('Saturday','Sunday'),'Weekend','Weekday'), ...
SELECT DATE_ADD(NOW(), INTERVAL 1 DAY) AS next_day; 这个查询将返回当前日期加上一天的结果。 常见问题及解决方法 问题:日期格式化错误 原因:可能是由于格式化字符串不正确或数据类型不匹配导致的。 解决方法:检查格式化字符串是否正确,并确保数据类型与格式化函数兼容。
执行sql String sql = "select * from app_user where id<10"; ResultSet resultSet = statement.executeQuery(sql); while (resultSet.next()) { System.out.println("id:" + resultSet.getObject("id") + "phone:" + resultSet.getObject("phone")); } //6.释放连接 resultSet.close(); ...
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Caused by: java.sql.SQLException: HOUR_OF_DAY 场景一、 问题描述/异常栈 Caused by: java.lang.IllegalArgumentException: HOUR_OF_DAY: 0 -> 1 at java.util.GregorianCalendar.computeTime(GregorianCalendar.java:2829) at java.util.Calendar.updateTime(Calendar.java:3393) at java.util.Calendar.getTime...