Here is a super simple SQL query to determine the size of all tables in a given database: SELECTTABLE_NAMEAS"Table",round(((data_length+index_length)/1024/1024),2)ASSize_in_MBFROMinformation_schema.TABLESWHEREtable_schema='my_db_name'ORDERBYSize_in_MBDESC ...
创建一个存储过程,用于查询表的大小: DELIMITER //CREATE PROCEDURE get_table_size(IN database_name VARCHAR(255), IN table_name VARCHAR(255))BEGINSELECT table_name, table_rows, data_length, index_lengthFROM information_schema.tablesWHERE table_schema = database_name AND table_name = table_name;...
a.table_name , concat(round(sum(DATA_LENGTH / 1024 / 1024) + sum(INDEX_LENGTH / 1024 / 1024) ,2) ,'MB') total_size , concat(round(sum(DATA_LENGTH / 1024 / 1024) , 2) ,'MB') AS data_size , concat(round(sum(INDEX_LENGTH / 1024 / 1024) , 2) ,'MB') AS index_size FR...
1118 - Row size too large. The maximum row size for the used table type, not counting BLOBs, is 65535. This includes storage overhead, check the manual. You have to change some columns to TEXT or BLOBs 翻译:1118 -行太大。所用表类型的最大行大小(不包括BLOBs)是65535。这包括存储开销,请...
then what will be the size of my table? do i need 'SUM_OVER_ALL_BTREE_KEYS(max_length_of_key + sizeof(char*) × 4)' as i have only hash keys? thanks in advance :) Shantonu Subject Views Written By Posted How to get size of memory table??
查看指定数据库下的所有表的空间占用情况 select table_name,round(sum(data_length/1024/1024),2) as size from information_schema.tables where table_schema='DB_NAME' group by table_name order by size ; -- 6. 查看指定数据库的某个表的大小 select concat(round(sum(data_length/1024/1024),2),...
query_cache_size query_cache_limit query_cache_min_res_unit query_cache_wlock_invalidate 1.1.2 事务相关参数 tx_isolation 和 tx_read_only 在8.0.3中移除,使用参数transaction_isolation 和transaction_read_only 替代 1.1.3 日志相关参数 expire_logs_days 设置binlog保留天数,从MySQL 8.0.11开始已经废弃,...
alter table ALGORITHM [=] {DEFAULT | INSTANT | INPLACE | COPY} COPY: 这种操作是在原始表的一个副本上进行的,表数据会逐行从原始表复制到新表。在此过程中,不允许进行并发的数据修改操作。 INPLACE: 这种操作避免了复制表数据,但可能会就地重建表。在操作的准备和执行阶段,系统可能会短暂地对表进行独占的...
CopySELECT table_schema AS "Database", ROUND(SUM(data_length + index_length) / 1024 / 1024, 2) AS "Size (MB)" FROM information_schema.TABLES GROUP BY table_schema; Depending on how many databases you have and how large they are, this command may take a minute or two to complete. ...
+ SUM_OVER_ALL_HASH_KEYS(sizeof(char*) × 2) + ALIGN(length_of_row+1, sizeof(char*)) then what will be the size of my table? do i need 'SUM_OVER_ALL_BTREE_KEYS(max_length_of_key + sizeof(char*) × 4)' as i have only hash keys? thanks in advance :) ShantonuNav...