* @param float $lat 纬度 * @param float $distance 距离(km) * @return array */ function getSquarePoint($lng, $lat, $distance) { $earthRadius = 6371; //地球半径,km $d_lng = 2 * asin(sin($distance / (2 * $earthRadius)) / cos(deg2rad($lat))); $d_lng = rad2deg($d_lng);...
CREATE DEFINER=`root`@`localhost` FUNCTION `getDistance`( lng1 float(10,7) ,lat1 float(10,7) ,lng2 float(10,7) ,lat2 float(10,7) ) RETURNS double begin declare d double; declare radius int; set radius = 6378140; #假设地球为正球形,直径为6378140米 set d = (2*ATAN2(SQRT(SIN((...
Rectangle rectangle = getRectangle(distance, userLng, userLat); //2.获取位置在正方形内的所有用户 List<User> users = userMapper.selectUser(rectangle.getMinX(), rectangle.getMaxX(), rectangle.getMinY(), rectangle.getMaxY()); //3.剔除半径超过指定距离的多余用户 users = users.stream() .filter(...
Double lon= shotlocal.get(0).getLon(); localDouble = shotlocal.get(0).getDistance(); System.err.println("最近的距离:" + localDouble + "。对应的经纬是:" +"(" + lat + "," + lon + ")"); } /*第一种求最近距离 ===*/ /** * 获取最短的距离 * @param lat * @param lon *...
1. 测试计算两个2维向量点的距离select euclidean_distance("-0.0781729444861412,0.110044464468956", "-0.12611718475818634,0.13194166123867035")2. 查询指定向量最相似的前5条SELECT face_id,euclidean_distance('-0.0781729444861412,0.110044464468956,0.06956595182418823,-0.04195471480488777,-0.13797412812709808,-0...
{SpatialContextcontext=SpatialContext.GEO;Rectanglerectangle=context.getDistCalc()//.calcBoxByDistFromPt(//context.makePoint(lng, lat),//radius * com.spatial4j.core.distance.DistanceUtils.KM_TO_DEG, context,null//);returnnewTuple4<>(rectangle.getMinX(), rectangle.getMaxX(), rectangle.getMinY(...
*/functiongetRad(d){varPI=Math.PI;returnd*PI/180.0; }/** 根据经纬度计算两点间距离@paramlng1@paramlat1@paramlng2@paramlat2@returns@constructor/ function CoolWPDistance(lng1,lat1,lng2,lat2){ var f = getRad((lat1 + lat2)/2); ...
I've seen a colleage use the following formula to get distance from the database, ( 6371 * acos( cos( radians(".$fLat.") ) * cos( radians( X(v.geo) ) ) * cos( radians( Y(v.geo) ) - radians(".$fLng.") ) + sin( radians(".$fLat.") ) * sin( radians( X(v.geo) ...
1、计算距离的公式比较长(网上查找),建一个mysql函数: delimiter $$ CREATE FUNCTION FUN_JW_DIST(lng1 double(15,9), lat1 double(15, 9), lng2 double(15,9), lat2 double(15,9)) RETURNS i...
Re: php mysql distance query Rick James December 05, 2010 12:26PM Re: php mysql distance query Alan Young December 05, 2010 05:50PM Re: php mysql distance query Rick James December 05, 2010 06:38PM Sorry, you can't reply to this topic. It has been closed....