SELECT WEEK(‘2016-01-03', 1) 1 2 3 -> 1 (该函数返回date在一年当中的第几周,date(01.03)是周日,默认是以为周日作为一周的第一天,函数在此处返回1可以有两种理解:1、第一周返回0,第二周返回1,... ,2、以当年的完整周开始计数,第一周返回1,第二周返回2,... ,最后一周返回53) -> 1 (week...
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ; select * from user where WEEKOFYEAR(FRO...
SELECT WEEK(‘2016-01-03', 1) 1 2 3 -> 1 (该函数返回date在一年当中的第几周,date(01.03)是周日,默认是以为周日作为一周的第一天,函数在此处返回1可以有两种理解:1、第一周返回0,第二周返回1,... ,2、以当年的完整周开始计数,第一周返回1,第二周返回2,... ,最后一周返回53) -> 1 (week...
2个参数形式WEEK()允许你指定星期是否开始于星期天或星期一。如果第二个参数是0,星期从星期天开始,如果第二个参数是1,从星期一开始。 mysql> select WEEK('1998-02-20'); -> 7 mysql> select WEEK('1998-02-20',0); -> 7 mysql> select WEEK('1998-02-20',1); -> 8 YEAR(date) 返回date的年...
utc_date()函数返回当前utc(世界标准时间)日期值,其格式为yyyy-mm-dd或者yyyymmdd; mysql> select utc_date(), utc_date()+0; +---+---+ | utc_date() | utc_date()+0 | +---+---+ | 2022-07-12 | 20220712 | +---+---+ 1 row in set ...
) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR...
select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 2 DAY) 前两week的第一天: select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 15 DAY) 前两week的最后一天: select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 9 DAY) ...
select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 2 DAY) 前两week的第一天: select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 15 DAY) 前两week的最后一天: select date_sub(curdate(),INTERVAL WEEKDAY(curdate()) + 9 DAY) ...
mysql> SELECT the_date, DAYNAME(the_date), WEEKDAY(the_date), DAYOFWEEK(the_date) FROM test; +---+---+---+---+ | the_date | DAYNAME(the_date)| WEEKDAY(the_date)| DAYOFWEEK(the_date)| | 2021-11-02 | Tuesday | 1 | 3 | | 2022-01-05 | Wednesday | 2 | 4 | ...
下面的查询选择了所有记录,其date_col的值是在最后30天以内:mysql> SELECT something FROM table WHERE TO_DAYS(NOW()) – TO_DAYS(...date_col) <= 30;DAYOFWEEK(date) 返回日期date的星期索引(1=星期天,2=星期一, ……7=星期六)。...mysql> selectDAYOFWEEK(‘1998-02-03’); -> 3 WEEKDAY(date...