A solution is presented for the equations of motion for the damped linear oscillator, Mx(double dot) + Cx(dot) + Kx = 0. The algorithm solves a transformed set of equations in terms of the modal variables of the undamped system and, at the same time, solves the adjoint equation of the...
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一个自由度振动系统的振动方程为mx'' + cx' + kx = F(t),其中m为质量,c为阻尼系数,k为劲度系数,F(t)为外力。求系统的频率响应函数。答案:根据振动方程,我们可以得到系统的特征方程为ms^2 + cs + k = 0,其中s为复变量。解这个特征方程得到系统的固有频率ωn = √(k/m)。频率
mx"+cx'+kx=0X是关于t的函数 相关知识点: 试题来源: 解析 我想你要问的是二阶的情况吧?当m,c,k=0时的情况很简单,就不写了.当为二阶常系数线性方程时,其通解有3种不同的情况原方程的特征方程为:mp2+cp+k=0(1)当特征方程有两个不等的实根 r1, r2 时原方程有两个特解 x1 = e^(r1×t) x...
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用dsolve（）函数可以求得微分方程的通解。>> syms x(t)>> syms m c k a w wc >> D2x=diff(x,2);Dx=diff(x,1);>> x=dsolve(m*D2x+c*Dx+k*x==k*a*sin(w*t)+c*a*wc)运行结果