<p>To find the molality of a sulfuric acid solution where the mole fraction of water is 0.86, we can follow these steps:</p><p><strong>Step 1: Determine the mole fraction of sulfuric acid (H2SO4)</strong> The mole fraction of a solute and solvent adds up
( 1.008 amu) + 16.00 amu = Mass of one molecules of water = Molar mass = ( 2 x atomic mass of H ) + atomic mass of O = 2 ( 1.008 g ) + 16.00 g = g H 2 O = 6.022 x 10 23 molecules of water = 1 mole H 2 O Fig 3.2 (P 87) One mole of common sbustances CaCO 3...