Use the Molarity Calculator to calculate the mass, volume or molar concentration required to prepare a solution of compound of known molecular weight.
The calculators on this page are independent and can be used in any order. The calculators are numbered because sometimes the results of one calculator are used as inputs to a later one. 1. Mass from volume & concentration Concentration: ...
An example of a molarity calculation using the Bio-Techne molarity calculator What is the mass of compound required to make a 10 mM stock solution in 10 ml of water given that the molecular weight of the compound is 197.13 g/mol? Enter 197.13 into the Molecular Weight (MW) box Enter 10...
This molarity calculator estimates the molar concentration of a solution by using the mass, volume and molecular weight. You can read more on the molar concentration and how to calculate the number of moles for a solution below the form. How does this molarity calculator work?
This online calculator converts the molar concentration of a solution to molar concentration and vice versa if the density of the solution is known.
Therefore, we need to dilute 0.005 L0.005 L (or 5 mL5 mL) of stock solution to a final volume of 1 L1 L to get a 200 ppm200 ppm NaOHNaOH solution. You can check Step 1 with this ppm to molarity calculator and check Step 2 with the solution dilution calculator! FAQs How do I ...
Be careful– the density of a solution is usually given in g/mL or g/cm³ or kg/m³! Our calculator will help you will all the conversions, so don't stress. Check our other useful tools for molar mass & solutions: Titration calculator⚗️ ...
An example of a molarity calculation using the Mass Molarity Calculator: What is the mass of the compound required to make a 10 mM stock solution in 10 ml of water, given that the molecular weight of the compound is 197.13 g/mol?
Gram needed to 2 liter solution: 2 (mol) * 60.06 (g/mol) = 120.12 g acetic acid Density of 100% acetic acid at 20°C is 1.048 g/cm3 Volume needed to 2 liter solution: 120.12 (g) / 1.048 (g/cm3) = 114.62 cm3 = 114.62 ml = 0.115 L acetic acid NB! Never start with addin...
liters of water = (250 ml)(1 L/1000 ml) liters of water = 0.25 L Finally, you're ready todetermine molarity. Simply express the concentration of KCl in water in terms of moles solute (KCl) per liters of solute (water): molarity of solution = mol KC/L water ...