CALCULATE THE MOLARITY OF AN ACETIC ACID SOLUTION WHICH IS 2% IONISED, THE PKA OF ACETIC ACID IS 4.74 相关知识点: 试题来源: 解析 4.74是指醋酸在水中的电离程度,通过这个数可以算出醋酸根的电离浓度再除以2%应该是他的浓度吧。10的-4.74次幂除以2%就是他的浓度(M) 不知道对不对。
All elements and compounds have molar masses (for elements) and molecular weights (for compounds). The mass of a substance (in grams) divided by its molecular weight/molar mass is the number of moles.Answer and Explanation: Become a member and unlock all Study Answers Start today. Try it ...
200 g of acetic acid are dissolved in enough water to make 1.5 L. What is the molarity of acetic acid solution? {eq}K_{a}= 1.8 x 10^{-5} {/eq} Molarity: Sequence wise calculation can be done to obtain the required molarity fr...
To calculate the molarity, we can use the formula {eq}M = \dfrac{N}{V} {/eq}, where {eq}N {/eq} is the total number of moles and {eq}V {/eq} is the volume of solution in liters. Answer and Explanation: Given Data:
Find the solubility of Ag3PO4 at pH 3.at pH 3, ksp= 1.3e-20The volume of 0.05 M H2SO4 required to neutralize 80 ml of 0.13 N NaOH will be: (a) 104 ml (b) 52 ml (c) 10.4 ml (d) 26 mlCalculate the pH and pOH for ...
Answer and Explanation: 8.64 mL = volume of vinegar = 0.00864 L 49.17 mL = volume of NaOH = 0.04917 L At neutralization, the moles of acid equal the moles of the base. For...
In this paper, Kalman filtering spectrophotometry is used to analyze and study p-acetaminophenol, p-nitrophenol, p-amin-ophenol and acetic acid in the course of synthesis of p-acetaminophenol, in which the selection of the Kalman filtering parameter is studied in detail. ...