CALCULATE THE MOLARITY OF AN ACETIC ACID SOLUTION WHICH IS 2% IONISED, THE PKA OF ACETIC ACID IS 4.74 相关知识点: 试题来源: 解析 4.74是指醋酸在水中的电离程度,通过这个数可以算出醋酸根的电离浓度再除以2%应该是他的浓度吧。10的-4.74次幂除以2%就是他的浓度(M) 不知道对不对。
200 g of acetic acid are dissolved in enough water to make 1.5 L. What is the molarity of acetic acid solution? {eq}K_{a}= 1.8 x 10^{-5} {/eq} Molarity: Sequence wise calculation can be done to obtain the required molarity fr...
For example, if 0.1000 mole or 5.905 g of acetic acid (HC2H3O2) is dissolved in 1.000 liter of solution (H2O), the solution will be 0.00134 mole/liter in H3O+, 0.00134 mole/liter in C2H3O2−, and 0.0987 mole/liter in un-ionized HC2H3O2. Chemically, this partial dissociation can be ...