Today lets learn about Modulus or Modulo or Modular Division in C programming language. Division Example10 / 5 = 2 (quotient) Modulo Division Example10 % 5 = 0 (remainder) Note:Division operation returns Quotient.Modulo Division operation returns Remainder. quotient = dividend / divisor;remainder...
Function reference Syntax reference Programming FAQ The C++ Modulus Operator Take a simple arithmetic problem: what's left over when you divide 11 by 3? The answer is easy to compute: divide 11 by 3 and take the remainder: 2. But how would you compute this in a programming language like ...
main.c: In function ‘main’: main.c:8:22: error: invalid operands to binary % (have ‘float’ and ‘float’) float result = x % y; ^ See the output – it says that invalid operands tomodulusoperator. How to find the remainder/modulus of two float or double numbers in C?
@Vlad- there's no good reason for it to be that way except that early hardware where C first ran defined the operation that way. The remainder function on negative numbers is pretty useless and one in practice invariably winds up fixing the result if negative numbers are a possibility. For...
9 RegisterLog in Sign up with one click: Facebook Twitter Google Share on Facebook modulus of deformation [′mäj·ə·ləs əv ‚dē‚fȯr′mā·shən] (mechanics) The modulus of elasticity of a material that deforms other than according to Hooke's law. ...
Java has %, the remainder operator, but does not have a built-in modulus operator or function. SignsDivision /Remainder %Modulus + + 7 / 4 = 1 7 % 4 = 3 7 mod 4 = 3 - + -7 / 4 = -1 -7 % 4 = -3 -7 mod 4 = 1 + - 7 / -4 = -1 7 % -4 = 3 7 mod -4 ...
90C0590C31CalmnessLinear programmingLipschitz modulusOptimal valueVariational analysisThe present paper is devoted to the computation of the Lipschitz modulus of the optimal value function restricted to its domain in linear programming under different types of perturbations. In the......
Our starting point is an upper bound on this modulus given in C谩novas et al. (4). In this paper we prove that this upper bound is attained if and only if the norm of the objective function coefficient vector is less than or equal to the critical objective size. This concept also ...
used in this method to classify the features. In the SVM method, the objective is to minimize\(\frac{1}{2}\left\| \omega \right\|^{2} + C\sum\nolimits_{i = 1}^{N} {\left( {\xi_{i} + \xi_{i}^{*} } \right)}\)within the linear loss function constraints provided ...
As a function of k, this is decreasing for all values greater than or equal to the mth primorial, so we get the following upper bound on all k such that p m # < k < p m + 1 # :B m = l n ( p m # ) m p m # 1 m This upper bound would work great in practice but ...