Math Kernel Library)是Intel提供的一个高性能的数学库,它提供了广泛的数学函数来优化各种数学运算,包括线性代数、快速傅里叶变换(FFT)、随机数生成等。MKL库也提供了内存管理函数,如mkl_malloc()和mkl_free(),以及线性代数函数,如cblas_dgemm()。下面我将分别介绍这些函数的用法: mkl_malloc() mkl_malloc()函数...
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C = (float*)mkl_malloc(M*K *sizeof(float),64);if(A ==NULL|| B ==NULL|| C ==NULL) { mkl_free(A); mkl_free(B); mkl_free(C);returnfalse; }//赋值inti =0;intj =0;//如果alloc是行在前列在后if(allocType ==0) { lda = M; ldb = N; ldc = M;for(i =0; i < N; ...
mkl_free(A); mkl_free(B); mkl_free(C); printf (" Example completed. \n\n"); return 0; } 根据[3], C++动态链接项目的makefile如下: PROGRAM = foo.exe inc = "../inc/" src = "../src/" mkl = "D:/mkl/IntelSWTools/compilers_and_libraries_2019.5.281/windows/mkl/include/" LIBS...
("\nERROR: Can't allocate memory for matrices. Aborting...\n\n");mkl_free(A);mkl_free(B);mkl_free(C);return1;}printf(" Intializing matrix data\n\n");for(i=0;i<(m*k);i++){A[i]=(double)(i+1);}for(i=0;i<(k*n);i++){B[i]=(double)(-i-1);}for(i=0;i<(m...
mkl_free(C);return1; } printf("Intializing matrix data \n\n");for(i =0; i < (m * k); i++) { A[i]= (double)(i +1); }for(i =0; i < (k * n); i++) { B[i]= (double)(-i -1); }for(i =0; i < (m * n); i++) { ...
mkl_free(A); mkl_free(B); mkl_free(C); return 1; } printf (" Intializing matrix data \n\n"); for (i = 0; i < (m*p); i++) { A[i] = (double)(i+1); } for (i = 0; i < (p*n); i++) { B[i] = (double)(-i-1); } for (i = 0; i < (m*n); i+...
MKL is free (as in beer, it's not OSS) for a long time, but it's redistribution is bulky (on Windows, NuGet compressed package is 173 MB and uncompressed binaries size is 481 MB) and downloads from Intel web site require stupid registration (and they do spam with marketing bullshit ...
mkl_free(B); mkl_free(C); printf ("Example completed. \n\n");return0; } (代码下载地址:https://software.intel.com/en-us/product-code-samples) 编译命令为: $ gcc -I/opt/intel/mkl/include dgemm_example.c -lmkl_core -lmkl_intel_lp64 -lmkl_intel_thread -liomp5 -lpthread -lm -...
mkl_free(A); mkl_free(B); mkl_free(C);return1; }printf(" Intializing matrix data \n\n");for(i =0; i < (m*p); i++) { A[i] = (double)(i+1); }for(i =0; i < (p*n); i++) { B[i] = (double)(-i-1); ...