class Solution { fun missingNumber(nums: IntArray): Int { var xor = 0 val size = nums.size for (i in 0 until size) { xor = xor xor nums[i] } for (i in 0..size) { xor = xor xor i } return xor } } 时间复杂度:O(n),其中n是数组nums的长度。 空间复杂度:O(1)。
classSolution {public:intmissingNumber(vector<int>&nums) {intsum =0, n =nums.size();for(auto &a : nums) { sum+=a; }return0.5* n * (n +1) -sum; } }; 这题还有一种解法,使用位操作Bit Manipulation来解的,用到了异或操作的特性,相似的题目有Single Number 单独的数字,Single Number II ...
Write a Scala program to find a missing number in an array of integers. Sample Solution: Scala Code: objectscala_basic{deftest(numbers:Array[Int]):Int={vartotal_num=0;total_num=numbers.length;varexpected_num_sum=0expected_num_sum=total_num*((total_num+1)/2);varnum_sum=0;for(i<-0t...
1、Find All Numbers Disappeared in an Array Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not appear in this array. Could you do it without extra space and in...
24. Find Missing Number in an Array of Numbers Between 10 and 20 Write a Python program to find the missing number in a given array of numbers between 10 and 20. Sample Solution-1: Python Code: import array as arr def test(nums): ...
public class Solution { public int missingNumber(int[] nums) { //首先对数组进行排序 Arrays.sort(nums); int startData=nums[0]; for(int i=1;i<nums.length;i++) { //检查数组是否连续 if((startData+1)==nums[i]) { startData=nums[i]; ...
MissingNums { public static void main(String[] args) { // one missing number printMissageNums(new int [] { 1, 2, 3, 4, 6 }, 6); // duplicate number is OK // printMissageNums(new int[] { 1, 2, 3, 4, 4, 5, 6 }, 8); // only one missing number the second solution ...
LeetCode Top Interview Questions 268. Missing Number (Java版; Easy) 题目描述 Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1: Input: [3,0,1]
Tätä sisältöä ei enää päivitetä säännöllisesti.Microsoftin tuotteiden elinkaarisivustostasaat lisätietoja tämän tuotteen, palvelun, teknologian tai ohjelmointirajapinnan tukemisesta.
LeetCode OJ:Missing Number (丢失的数) Given an array containingndistinct numbers taken from0, 1, 2, ..., n, find the one that is missing from the array. For example, Givennums=[0, 1, 3]return2. Note: Your algorithm should run in linear runtime complexity. Could you implement it ...